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agasfer [191]
3 years ago
6

Enter the net ionic equation representing aqueous acetic acid neutralized by aqueous barium hydroxide.

Chemistry
1 answer:
IrinaK [193]3 years ago
6 0

Answer:

The answer to your question is below

Explanation:

Data

Aqueous acetic acid

Aqueous barium hydroxide

Formula

Acetic acid    CH₃CH₂COOH

Barium hydroxide   Ba(OH)₂

Neutralization reaction

        CH₃CH₂COOH    +    Ba(OH)₂      ⇒  Ba( CH₃CH₂COO)₂ + H₂O

                                                                    Barium acetate + H₂O

Barium acetate =  Ba( CH₃CH₂COO)₂ = Ba(C₃H₅O₂)₂

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Answer:

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Na⁺       11      10

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10.moles of glucose = 450g/180.16 g/mol =2.50 moles

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7 0
2 years ago
Explain why the quantum number set (3, 2, 3, -½) is not possible for an electron in an atom
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7 0
3 years ago
Does adding 1 mol of NaCl to 1 kg of water lower the vapor pressure of water to the same extent, a lesser extent, or a greater e
igor_vitrenko [27]

Answer:

Adding 1 mol of NaCl to 1 kg of water lower the vapor pressure of water <em><u>to the same extent</u></em>  by adding 1 mol of C_06H_{12}O_6 to 1 kg of water.

Explanation:

1) Moles of NaCl ,n_1=1 mol

Mass of water = m= 1 kg = 1000 g

Moles of water = n_2=\frac{1000 g}{18 g/mol}=55.55 mol

Vapor pressure of the solution = p

Vapor pressure of the pure solvent that is water = p_o=17.5 Torr

Mole fraction of solute(NaCl)= \chi_1=\frac{n_1}{n_1+n_2}

\frac{p_o-p}{p_o}=\frac{n_1}{n_1+n_2}

\frac{17.5 Torr-p}{17.5 Torr}=\frac{1 mol}{1 mol+55.55 mol}

p=17.19 Torr

The vapor pressure for the NaCl solution at 17.19 Torr.

2) Moles of sucrose ,n_1=1mol

Mass of water = m  = 1 kg = 1000 g

Moles of water = n_2=\frac{1000 g}{18 g/mol}=55.55 mol

Vapor pressure of the solution = p'

Vapor pressure of the pure solvent that is water = p_o=17.5 Torr

Mole fraction of solute ( glucose)= \chi_1=\frac{n_1}{n_1+n_2}

\frac{p_o-p}{p_o}=\frac{n_1}{n_1+n_2}

\frac{17.5 Torr-p}{17.5 Torr}=\frac{1 mol}{1 mol+55.55 mol}

p'=17.19 Torr

The vapor pressure for the glucose solution at 17.19 Torr.

p = p' = 17.19 Torr

Adding 1 mol of NaCl to 1 kg of water lower the vapor pressure of water to the same extent  by adding 1 mol of C_06H_{12}O_6 to 1 kg of water.

3 0
3 years ago
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