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Reil [10]
3 years ago
6

The force involves the attraction between objects with mass. Strong nuclear. Gravitational. Electromagnetic. Weak nuclear

Physics
2 answers:
dexar [7]3 years ago
8 0

Answer:       gravitational force or gravitational pull involves the attraction between objects with mass

Explanation:

Viktor [21]3 years ago
4 0
The answer is Gravitational.
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Assuming that the angle is the same for both ropes, then D. is the answer.  You have to consider also if the ropes are close together or far apart and if the force to move the object is in line with the ropes or perpendicular to them.
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In the figure below the pulley is a solid disk of mass M and radius R with rotational inertia MR 2/2. Two blocks one of mass m a
matrenka [14]
Assuming you are looking for the acceleration a:

1.m_1a = T_1 -m_1g
2.m_2a = m_2g - T_2
where T is the tension and a is the acceleration of the blocks. The acceleration of the two blocks and the acceleration of the pulley must be equal.

The torque on the pulley is given by:
3.\tau = \overrightarrow r \times \overrightarrow F = (T_2 - T_1)R = I\alpha = \frac{1}{2} MR^2 \frac{a}{R}
where I = \frac{1}{2} mR^2 and a = \alpha R.

Combining the three equations:
T_2 - T_1 = \frac{1}{2} Ma \\ m_2g - m_2a -m_1g - m_1a = (m_2-m_1)g - (m_1 + m_2)a = \frac{1}2}Ma \\ \\ a = \frac{(m_2 - m_1)g}{m_1 + m_2 + \frac{1}{2}M }
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3 years ago
When cleaning a storage battery you can use a solution of water and ammonia or solution of water and
Anettt [7]
Water and baking soda can be used, too.
7 0
3 years ago
A 40 kg boy on a skateboard throws a 2 kg ball at 20 m/s to the left. How fast did the boy move to the right on his skateboard?
sergey [27]
According to my examination I have confirmed that I do NOT repeat do NOT know this .
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As you may well know, placing metal objects inside a microwave oven can generate sparks. Two of your friends are arguing over th
poizon [28]

Answer:

4.048\times 10^{-7}\ m

Explanation:

h = Planck's constant = 6.626\times 10^{-34}\ m^2kg/s

c = Speed of light = 3\times 10^8\ m/s

E = Energy = 4.91\times 10^{-19}\ J

Wavelength ejected is given by

\lambda=\dfrac{hc}{E}\\\Rightarrow \lambda=\dfrac{6.626\times 10^{-34}\times 3\times 10^8}{4.91\times 10^{-19}}\\\Rightarrow \lambda=4.048\times 10^{-7}\ m

The maximum wavelength in angstroms of the radiation that will eject electrons from the metal is 4.048\times 10^{-7}\ m

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3 years ago
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