Potential energy can be calculated by the formula Pe=mgh. Plug in your values:
Pe=mgh
Pe=(6 kg)(9.8m/s^2)(100 m)
Pe=5880 kg x m^2/s^2, or 5880 Joules
Answer:
if balanced reaction then 2 NaOH + MgSO4 → Mg(OH)2 + Na2SO4
Explanation:
Answer:
mass of hydrogen in lake = 11.19% of 12
= 1.3428
check if question is correct or not
Explanation:
Answer:
For the wavelenth of light spectrum, I believe the order would be red visible light, infrared, microwaves and radio waves.
Answer:
Here's what I get.
Explanation:
The MO diagrams of KrBr, XeCl, and XeBr are shown below.
They are similar, except for the numbering of the valence shell orbitals.
Also, I have drawn the s and p orbitals at the same energy levels for both atoms in the compounds. That is obviously not the case.
However, the MO diagrams are approximately correct.
The ground state electron configuration of KrF is

KrF⁺ will have one less electron than KrF.
You remove the antibonding electron from the highest energy orbital, so the bond order increases.
The KrF bond will be stronger.