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Contact [7]
3 years ago
12

A technical machinist is asked to build a cubical steel tank that will hold 60L of water.Calculate in meters the smallest possib

le inside length of the tank. Round your answer to the nearest
Physics
1 answer:
den301095 [7]3 years ago
7 0

Answer:

Explanation:

Given

Total volume of tank V=60\ L\approx 60\times 10^{-3}\ m^3

Suppose a is the side of cubical tank

volume of cubical tank a^3

a^3=60\times 10^{-3}

a=3.909\times 10^{-1}\ m

a=0.39\ m

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Determine which law is appropriate for solving the following problem.
Nostrana [21]

Charles Law

Explanation:

Step 1:

It is given that the original volume of the gas is 250 ml at 300 K temperature and 1 atmosphere pressure. We need to find the volume of the same gas when the temperature is 350 K and 1 atmosphere pressure.

Step 2:

We observe that the gas pressure is the same in both the cases while the temperature is different. So we need a law that explains the volume change of a gas when temperature is changed, without any change to the pressure.

Step 3:

Charles law provides the relationship between the gas volume and temperature, at a given pressure

Step 4:

Hence we conclude that Charles law can be used.

8 0
3 years ago
Read 2 more answers
A car’s tire rotates 5.25 times in 3 seconds. What is the tangential velocity of the tire?
Lena [83]

The tangential velocity of the car's tire is the product of the angular velocity and radius of the car's tire which is 11(r) m/s.

<h3>Angular velocity of the tire</h3>

The angular velocity of the tire is the rate of change of angular displacement of the tire with time.

The magnitude of the angular velocity of the tire is calculated as follows;

ω = 2πN

where;

  • N is the number of revolutions per second

ω = 2π x (5.25 / 3)

ω =  11 rad/s

<h3>Tangential velocity of the tire</h3>

The tangential velocity of the car's tire is the product of the angular velocity and radius of the car's tire.

The magnitude of the tangential velocity is caculated as follows;

v = ωr

where;

  • r is the radius of the car's tire

v = 11r m/s

Learn more about tangential velocity here: brainly.com/question/25780931

4 0
2 years ago
describe an experiment to show how the frequency of a note emitted by a vibrating string depends on the tension of the string
mart [117]
Easy ! 

Take any musical instrument with strings ... a violin, a guitar, etc.

The length of the vibrating part of the strings doesn't change ...
it's the distance from the 'bridge' to the 'nut'.

Pluck any string.  Then, slightly twist the tuning peg for that string,
and pluck the string again.

Twisting the peg only changed the string's tension; the length
couldn't change.

-- If you twisted the peg in the direction that made the string slightly
tighter, then your second pluck had a higher pitch than your first one.

-- If you twisted the peg in the direction that made the string slightly
looser, then your second pluck had a lower pitch than the first one.
3 0
3 years ago
A shopper pushes a 5.32 kg grocery cart with a 12.7 N force directed at -28.7° below horizontal. A friction force of 8.33 N push
atroni [7]

Answer:

0.8214 m/s^2

Explanation:

Fnet= Fpushed - Ffriction

Fpushed = 12.7N      Ffriction = 8.33N

Fnet = 12.7N - 8.33N = 4.37N

Fnet= mass(acceleration)

Fnet = 4.37N    mass = 5.32 kg

4.37N = 5.32 kg(acceleration)

acceleration= 0.8214 m/s^2

3 0
3 years ago
10. Luther is designing a roller coaster for an amusement park. At one point, the roller coaster will enter a horizontal loop at
Charra [1.4K]

Answer:

centripital acceleration= v^2/r

r = v^2/a

r=31.8×31.8/29

r=34.8703m

Explanation:

the maximum acceleration is obtained with minimum radius.

3 0
2 years ago
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