Question

A technical machinist is asked to build a cubical steel tank that will hold 60L of water.Calculate in meters the smallest possible inside length of the tank. Round your answer to the nearest

Answer 1

Answer:

Explanation:

Given

Total volume of tank $V=60\ L\approx 60\times 10^{-3}\ m^3$

Suppose a is the side of cubical tank

volume of cubical tank $a^3$

$a^3=60\times 10^{-3}$

$a=3.909\times 10^{-1}\ m$

$a=0.39\ m$