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Scrat [10]
2 years ago
10

Which of the following procedures is used during the fractional distillation of petroleum?

Chemistry
1 answer:
dem82 [27]2 years ago
7 0
Increase at the temperature
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Two different atoms have four protons each and the same mass. However, one has a positive charge while the other is neutral. Des
seraphim [82]

The possible number and location of all subatomic are one of them is electrically neutral, while the other has a stable electronic configuration.

<h3>What are subatomic particles?</h3>

Subatomic particles are those particles that are present inside the atoms. They are electron, neutron, and proton. They are charged particles, protons are positively charged, electrons are negatively charged and neutrons are neutral.

The protons and electrons totally contribute to the atomic mass of the elements.

Thus, the subatomic particles are electrically neutral and stable to electronic configurations.

To learn more about subatomic particles, refer to the below link:

brainly.com/question/13303285

#SPJ1

8 0
1 year ago
What is the formula for sulfur hexa fluoride?
vlabodo [156]
S2F6, is the correct answer I believe!
6 0
3 years ago
Read 2 more answers
Please help! 20 Points!!!
lorasvet [3.4K]

Answer:

I just did it home slice the first one's Ag+ and Zn2+ and the second one is A

Explanation:

I just did the assignment

7 0
2 years ago
Read 2 more answers
What are the half-reactions for a galvanic cell with Zn and Mg electrodes?
Alona [7]

the half-reactions

cathode : Zn²⁺ (aq) + 2e⁻ ---> Zn (s)  

anode : Mg (s) → Mg²⁺ (aq) + 2e−

a balanced cell reaction

Zn²⁺(aq) + Mg(s)→ Zn(s) + Mg²⁺ (aq)

<h3 /><h3>Further explanation</h3>

Given

Zn and Mg electrodes

Required

The half-reactions for a galvanic cell

Solution

To determine the reaction of a voltaic cell, we must determine the metal that serves as the anode and the metal that serves as the cathode.

To determine this, we can either know from the standard potential value of the cell or use the voltaic series

1. voltaic series

<em>Li-K-Ba-Ca-Na-Mg-Al-Mn- (H2O) -Zn-Cr-Fe-Cd-Co-Ni-Sn-Pb- (H) -Cu-Hg-Ag-Pt-Au </em>

The more to the left, the metal is more reactive (easily release electrons) and the stronger reducing agent

So the metal on the left will easily undergo oxidation and function as anode

Since Mg is located to the left of Zn, then Mg functions as anode and Zn as a cathode

2. Standard potentials cell of Mg and Zn metals :

Mg2+ + 2e– → Mg E° = -2,35 V

Zn2+ + 2e– → Zn E° = -0,78 V

The anode has a smaller E°, then Mg is the anode and Zn is the cathode.

7 0
3 years ago
A sample of metal has a mass of 24.64 g, and a volume of 5.91 mL. What is the density of this metal?
dlinn [17]

Answer:

\boxed {\boxed {\sf 4.17 \ g/mL}}

Explanation:

We are asked to find the density of a metal. Density is the mass per unit volume. It is calculated by dividing the mass by the volume.

\rho= \frac{m}{v}

The mass of the metal sample is 24.64 grams and the volume is 5.91 milliliters. We can substitute these values into the formula.

  • m= 24.64 g
  • v= 5.91 mL

\rho=\frac{24.64 \ g }{5.81 \ mL}

Divide.

\rho= 4.169204738 \ g/mL

The mass measurement has 4 significant figures the volume measurement has 3 significant figures. Our answer for density must match the least number of significant figures, which is 3.

For the number we calculated, that is the hundredth place. The 9 in the thousandth place tells us to round the 6 up to a 7.

\rho \approx 4.17 \ g/mL

The density of this metal is approximately <u>4.17 grams per milliliter.</u>

3 0
2 years ago
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