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Scrat [10]
3 years ago
10

Which of the following procedures is used during the fractional distillation of petroleum?

Chemistry
1 answer:
dem82 [27]3 years ago
7 0
Increase at the temperature
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How many grams of NaF form when .5 mol of HF reacts with excess Na2SiO3?
IgorLugansk [536]

Answer:

5.25g

Explanation:

We'll begin by writing the balanced equation for the reaction. This is shown below:

Na2SiO3 + 8HF → H2SiF6 + 2NaF + 3H2O

From the balanced equation above,

8 moles of HF reacted to produce 2 moles of NaF.

Therefore, 0.5 moles of HF will react to produce = (0.5 x 2)/8 = 0.125 mole of NaF.

Next, we shall convert 0.125 mole of NaF to grams.

This is illustrated below:

Mole of NaF = 0.125 mole

Molar mass of NaF = 23 + 19 = 42g/mol

Mass of NaF =..?

Mass = mole x molar mass

Mass of NaF = 0.125 x 42

Mass of NaF = 5.25g

Therefore, 5.25g of NaF is produced from the reaction.

7 0
2 years ago
A 2.000 g sample of CoCl2.xH2O is dried in an oven. When the anhydrous salt is removed from the oven, its mass is 1.565 g. What
Mashutka [201]

The value of X is 2

The total amount of sample taken is 2.00 g

The amount of sample left in the oven after drying is 1.565g

The amount of sample lost (mass of water driven out) = Total sample-Anhydrous salt left in the oven

                                 = 2.00 - 1.565

                                = 0.435 grams

The moles of anhydrous salt present in the hydrate = 1.565g/129.83g/mol = 0.01205

The moles of water present in the hydrate = 0.4350g/18.01g/mol = 0.02415

Therefore the ratio of these two are in 1:2 ratio

The complete chemical reaction is   CoCl2.2H20

To know more about the Similar calculation and explanation click here:

brainly.com/question/14967837

#SPJ4

6 0
1 year ago
The decomposition of NH4HS is endothermic: NH4HS(s)⇌NH3(g)+H2S(g) Part A Which change to an equilibrium mixture of this reaction
shepuryov [24]

Explanation:

According to Le Chatelier's principle, any disturbance caused in an equilibrium reaction will shift the equilibrium in a direction that will oppose the change.

As the given reaction is as follows.

       NH_{4}HS(s) \rightleftharpoons NH_{3}(g) + H_{2}S(g)

(a)  When increase the temperature of the reactants or system then equilibrium will shift in forward direction where there is less temperature. It is possible for an endothermic reaction.

Thus, formation of H_{2}S will increase.

  • (b)  When we decrease the volume (at constant temperature) of given reaction mixture then it implies that there will be increase in pressure of the system. So, equilibrium will shift in a direction where there will be decrease in composition of gaseous phase. That is, in the backward direction reaction will shift.

Hence, formation of H_{2}S will decrease with decrease in volume.

  • When we increase the mount of NH_{4}HS then equilibrium will shift in the direction of decrease in concentration that is, in the forward direction.

Thus, we can conclude that formation of H_{2}S will increase then.

3 0
3 years ago
Determine the rate of a reaction that follows the rate law rate = k a m b i where
ikadub [295]
(missing part of your question):
when we have K = 1 x 10^-2 and [A] = 2 M & [B] = 3M & m= 2 & i = 1
So when the rate = K[A]^m [B]^i
and when we have m + i = 3 so the order of this reaction is 3 So the unit of K is L^2.mol^-2S^-1
So by substitution:
∴ the rate = (1x 10 ^-2 L^-2.mol^-2S^-1)*(2 mol.L^-1)^2*(3mol.L^-1)
                 = 0.12 mol.L^-1.S^-1
6 0
3 years ago
Give an example of a balanced force.
lutik1710 [3]

Answer:

When two forces are the same strength but act in opposite direction, they are called balanced forces. Again, tug-of-war is a perfect example. If the people on each side of the rope are pulling with the same strength, but in the opposite direction, the forces are balanced. The result is no motion.

Explanation:

Hope this helps!

7 0
3 years ago
Read 2 more answers
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