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Alona [7]
2 years ago
8

Drop a paper a piece of thermocol and a piece of plastic from a height of 10 to 15 feet not the time for each object to hit the

ground why does paper take more time than thermocol and thermocol more than the plastic piece make the paper to fell down in such a way that it should hit the ground before all of them and how does it happen
​
Physics
1 answer:
lisov135 [29]2 years ago
4 0

Answer:

Explanation:

According to Newton's law of gravitation , all objects should take same time to fall from same height , but it does not happen when we see a paper , a thermocol and a plastic paper to fall .

It happens due to air resistance . In case of paper , this is most pronounced , so it falls slowest . In case of plastic paper , the resistance is least so it falls fastest .

If we squeeze the piece of paper to make a lump so that it does not remain flat , it will fall the fastest , because in this case the air resistance on it becomes the least .

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Two point charges of -7uC and 4uC are a distance of 20
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Answer:

Approximately 0.979 J.

Explanation:

Assume that the two charges are in vacuum. Apply the coulomb's law to find their initial and final electrical potential energy \mathrm{EPE}.

\displaystyle \mathrm{EPE} = \frac{k \cdot q_1 \cdot q_2}{r},

where

  • The coulomb's constant k = 8.99\times 10^{9}\; \rm N\cdot m^{2} \cdot C^{-2},
  • q_1 and q_2 are the sizes of the two charges, and
  • r is the separation of (the center of) the two charges.

Note that there's no negative sign before the fraction.

Make sure that all values are in SI units:

  • q_1 = -7\rm \;\mu C = -7\times 10^{-6}\; C;
  • q_2 = 4\rm \;\mu C = 4\times 10^{-6}\; C;
  • Initial separation: \rm 20\; cm = 0.20\; cm;
  • Final separation: \rm 90\; cm = 0.90\; cm.

Apply Coulomb's law:

Initial potential energy:

\begin{aligned} \frac{k \cdot q_1 \cdot q_2}{r} &= \frac{8.99\times 10^{9}\times (-7\times 10^{-6})\times 4\times 10^{-6}}{0.20}\\&= \rm -1.2586\; J\end{aligned}.

Final potential energy:

\begin{aligned} \frac{k \cdot q_1 \cdot q_2}{r} &= \frac{8.99\times 10^{9}\times (-7\times 10^{-6})\times 4\times 10^{-6}}{0.90}\\&= \rm -0.279689\; J\end{aligned}.

The final potential energy is less negative than the initial one. In other words, the two particles gain energy in this process. The energy difference (final minus initial) will be equal to the work required to move them at a constant speed.

\begin{aligned}\text{Work required} &= \text{Final EPE} - \text{Initial EPE}\\&= \rm  -0.279689\; J - (-1.2586\; J)\\&\approx 0.979\; J\end{aligned}.

8 0
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Answer:

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Explanation:

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4 0
2 years ago
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Answer:

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Explanation:

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Answer:

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Explanation:

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Answer:

This is the simplified definition.

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The main goal of physics is to explain how things move in space and time and understand how the universe behaves.

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