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aalyn [17]
4 years ago
11

The water molecule H2O is polar because it contains two polar single bonds and A. its molecule has a linear shape. B. molecules

that contain polar bonds are always polar. C. its molecule has a bent shape. D. the attractions between water molecules are strong. 
Chemistry
2 answers:
Musya8 [376]4 years ago
8 0

Answer: Option (C) is the correct answer.

Explanation:

Water is a polar molecule because it has two polar single bonds and also it has bent shape structure.

Since the oxygen atom of water has two lone pair of electrons and also dipole moment is more towards the oxygen atom. As a result, there will be increase in electron density across the oxygen atom which will induce a negative charge on oxygen and positive charge on hydrogen atom.

Thus, water molecule becomes polar in nature.

Anni [7]4 years ago
4 0
<span>c. it has a bent shape</span>
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The second best answer is its group on the periodic table.

That answer depends on the actual reason. The number of protons determines which element you are talking about.

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If oxygen has a molar mass of 16.0 g/mole, carbon has a molar mass of 12.0 g/mole and hydrogen has a molar mass of 1.01 g/mole,
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The number of mole of ethanol present in the beaker is 0.217 mole

Description of mole
The mole of a substance is related to it's mass and molar mass according to the following equation:
Mole = mass / molar mass

How to determine the mole of C₂H₅OH
From the question given above, the following data were obtained:
Mass of C₂H₅OH = 10 g
Molar mass of C₂H₅OH = (12×2) + (1.01×5) + 16 + 1.01 = 46.06 g/mol
Mole of C₂H₅OH =?

Mole = mass / molar mass
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Mole of C₂H₅OH = 0.217 mole


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5 0
2 years ago
What percentage of radioactive substance remains after two half-lives
Ksju [112]

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After 2 half-lives there will be 25% of the original isotope, and 75% of the decay product. After 3 half-lives there will be 12.5% of the original isotope, and 87.5% of the decay product. After 4 half-lives there will be 6.25% of the original isotope, and 93.75% of the decay product.

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3 0
3 years ago
What is the theoretical yield of sodium oxide (Na₂O) in grams when 20.0g of calcium oxide (CaO) reacts with an excess amount of
ad-work [718]

Answer:

22.1g

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

CaO + 2NaCl —> Na2O + CaCl2

Next, we shall determine the mass of CaO that reacted and the mass of Na2O produced from the balanced equation.

This is illustrated below:

Molar mass of CaO = 40 + 16 = 56g/mol

Mass of CaO from the balanced equation = 1 x 56 = 56g

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Mass of Na2O from the balanced equation = 1 x 62 = 62g

From the balanced equation above,

56g of CaO reacted to produce 62g of Na2O.

Finally, we can determine the theoretical yield of Na2O as follow:

From the balanced equation above,

56g of CaO reacted to produce 62g of Na2O.

Therefore, 20g of CaO will react to produce = (20 x 62)/56 = 22.1g of Na2O.

Therefore, the theoretical yield of Na2O is 22.1g

6 0
3 years ago
Read 2 more answers
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