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IrinaVladis [17]
3 years ago
14

Grignard reactions are usually performed in ether solvent. Which statement below does not identify a safety concern associated w

ith the use of diethyl ether in the lab?
A. Diethyl ether has a very low miscibility in waterB. Diethyl ether can form explosive peroxides when exposed to air and sunlightC. Diethyl ether has a powerful anesthetic effect if inhaledD. Diethyl ether is highly flammable, with a flash point of -40 degrees Celsius
Chemistry
1 answer:
nikdorinn [45]3 years ago
6 0

Answer: A.  Diethyl ether has a very low miscibility in wate

The fact that the diethyl ether is miscible or not in water <u>does not imply a ris</u>k for the person who is working with this reagent in the laboratory.

However, the fact that diethyl ether forms explosive peroxides and that it is highly flammable implies that there is a risk of explosion when exposed to air and sunlight. On the other hand, as option C mentions, if a person inhales a large quantity of this reagent, they may lose consciousness and suffer some injury when fainting, due to the powerful anesthetic effect of this reagent.<u> In conclusion, options B, C and D are statements that imply safety problems associated with the use of diethyl ether in the laboratory, while option A does not imply it.</u>

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Given molecule:

CH3-CH2-CH2-CH2-CH2-CH2-CH3

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3 years ago
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3 years ago
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Calculate the heat absorbed by a sample of water that has a mass of 45.00 g when the temperature increases from 21.0oC to 38.5 o
Elenna [48]

Answer:

The heat absorbed by the sample of water is 3,294.9 J

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

The sensible heat of a body is the amount of heat received or transferred by a body when it undergoes a temperature variation (Δt) without there being a change of physical state (solid, liquid or gaseous). Its mathematical expression is:

Q = c * m * ΔT

Where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

In this case:

  • Q=?
  • m= 45 g
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Replacing:

Q= 4.184 \frac{J}{g*C} * 45 g* 17.5 C

Solving:

Q=3,294.9 J

<u><em>The heat absorbed by the sample of water is 3,294.9 J</em></u>

<u><em></em></u>

8 0
3 years ago
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The oxidation number of elements in equation below are,

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O.N of N in NH₃ = -3
O.N of Ca in Ca(ClO)₂ and CaCl₂ = +2
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Oxidation:
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Reduction:
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Result:
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suter [353]
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