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worty [1.4K]
4 years ago
7

The charges are in a uniform electric field whose direction makes an angle of 36.3 ∘∘ with the line connecting the charges. What

is the magnitude of this field if the torque exerted on the dipole has magnitude 7.60×10−9 N⋅mN⋅m ?
Physics
1 answer:
azamat4 years ago
8 0

Answer:

E=828N/C

Explanation:

Suppose the point charges are q1=-500nC

q2=+500nC

Distance(l)=3.10mm

Now to calculate dipole moment:

Dipole moment (p)=q*l

=(5.0*10'-9C)(3.10*10'-3m)

p=15.50*10'-12C.m

Now to calculate magnitude:

E=torque(£)/[email protected]=7.6*10'-9/(15.50*10'-12C.m)(sin36.3)

E=7.6*10'-9/9.17*10'-12

E=828N/C

Or

E=8.28*10'2N/C

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Where the bold indicate vectors, W is work, F is force and d is displacement.

The work energy theorem relates work and kinetic energy.

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Learn more here:  brainly.com/question/17056946

8 0
3 years ago
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Answer:

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Explanation:

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Hope this helps!

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