Answer:
1. the one with the raito
2. the one that stubbed their toe
Explanation:
Answer:

Explanation:
Given that,
The distance between two spheres, r = 25 cm = 0.25 m
The capacitance, C = 26 pF = 26×10⁻¹² F
Charge, Q = 12 nC = 12 × 10⁻⁹ C
We need to find the work done in moving the charge. We know that, work done is given by :

Put all the values,

So, the work done is
.
Answer:
x = 0.237
y = 0.0789
Explanation:
Vector with direction 18.4° and magnitude 0.250 has x and y components of:
x = 0.250 cos 18.4°
x = 0.237
y = 0.250 sin 18.4°
y = 0.0789
Answer:
649kg/m^3
Explanation:
Let p be the density of this particular object.
Formula for density:

We can substitute the givenmass and volume to find density of the object.

Therefore the density of this object is 649kg/m^3.