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3 years ago

Another word for state of matter is _________.

Physics

2 answers:

Firdavs [7]3 years ago

8 0

I would think phase... none of the others make sense

SSSSS [86.1K]3 years ago

7 0

Answer:

Explanation:

Another name for state if matter is phase of matter

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A man has a weight of 100 Newtons. How much work is done if he climbs 4meters up a ladder?

Aliun [14]

Answer:

400 J

Explanation:

Work is done when a force that is applied to an object moves that object.

The work is calculated by multiplying the force by the amount of movement of an object

W = F * d

here the man has to work against the gravitational field. (against his weight)

F =100 N

Work done = F * d

= 100 * 4

= 400 J

7 0

4 years ago

Light is electromagnetic radiation composed of electric and magnetic field components. The electromagnetic spectrum includes lig

ivanzaharov [21]

Answer:

radio waves

Explanation:

radio waves

3 0

3 years ago

A student produces a power of p = 0.87 kw while pushing a block of mass m = 75 kg on an inclined surface making an angle of Î¸ =

Paul [167]

When block is pushed upwards along the inclined plane

the net force applied on the block will be given as

$F_{net} = mg sin\theta + \mu_k mg cos\theta$

here we know that

m = 75 kg

$\theta = 8.5 degree$

$\mu_k = 0.16$

now plug in all values into this

$F_{net} = 75\times 9.8 sin8.5 + 0.16 \times 75\times 9.8 cos8.5$

$F = 225 N$

now for finding the power is given as

$P = Fv$

$0.87 \times 10^3 = 225 \time v$

$v = \frac{870}{225} = 3.87 m/s$

6 0

3 years ago

Given the Earth's density as 5.5 g/cm3 and the Moon's density as 3.34 g/cm3, determine the Roche limit for the Moon orbiting the

Assoli18 [71]

Answer:

The Roche limit for the Moon orbiting the Earth is 2.86 times radius of Earth

Explanation:

The nearest distance between the planet and its satellite at where the planets gravitational pull does not torn apart the planets satellite is known as Roche limit.

The relation to determine Roche limit is:

$Roche\ limit=2.423\times R_{P}\times\sqrt[3]{\frac{D_{P} }{D_{M} } }$ ....(1)

Here $R_{P}$ is radius of planet and $D_{P}\ and\ D_{M}$ are density of planet and moon respectively.

According to the problem,

Density of Earth, $D_{P}$ = 5.5 g/cm³

Density of Moon, $D_{M}$ = 3.34 g/cm³

Consider $R_{E}$ be the radius of the Earth.

Substitute the suitable values in the equation (1).

$Roche\ limit=2.423\times R_{E}\times\sqrt[3]{\frac{5.5 }{3.34 } }$

$Roche\ limit= 2.86R_{P}$

8 0

3 years ago

I require assistance, please. I would highly appreciate your response. It is a question on the states of matter. I forgot some o

Alex17521 [72]

Fundamental States,
Non-classical States.
Solid,
Liquid,
Gas and
Plasma.

7 0

4 years ago

Read 2 more answers