Answer:
0.07°C
Explanation:
<u>solution:</u>
the speed of a sound in water is<u>:</u>
v(T)=1480+4(T-4°C)
<u>at 4°C the travel time is:</u>
t(4◦C) = (
7600 × 103 m
)
/ (1480 m/s) = 5202.7 s
<u>5°C, the travel time is:</u>
t(5◦C) = (
7600 × 103 m
)
/ (1484 m/s) = 5188.7 s
<u>one degree C corresponds to a ∆t of 14 s so temperature difference is:</u>
ΔT=1 s/14 s=0.07◦C
Answer:
21.4 mph
Explanation:
Circumference of tire in FEET = pi * d = pi * 1 ft = pi feet
pi feet x 600 rot/min * 60 min /hr * 1 mile / 5280 feet = 21.4 mph
Answer:
The force of static friction acting on the luggage is, Fₓ = 180.32 N
Explanation:
Given data,
The mass of the luggage, m = 23 kg
You pulled the luggage with a force of, F = 77 N
The coefficient of static friction of luggage and floor, μₓ = 0.8
The formula for static frictional force is,
Fₓ = μₓ · η
Where,
η - normal force acting on the luggage 'mg'
Substituting the values in the above equation,
Fₓ = 0.8 x 23 x 9.8
= 180.32 N
Hence, the minimum force require to pull the luggage is, Fₓ = 180.32 N
Answer:
a=positive
b=0
c=positive
d=negative
Explanation:
a=acceleration depends on the speed and time. if the speed and time are increasing at the same rate, the acceleration value will be positive as the vehicle is speeding up.
b=the speed and time are not increasing, therefore the vehicle is either stationary or travelling at a steady pace.
c=same explanation as a
d=the speed and time are not increasing at the same rate as the speed is decreasing. this means that the car is slowing down