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Fantom [35]
3 years ago
14

What is the volume in L of 3.8 kg of this liquid?

Chemistry
1 answer:
DedPeter [7]3 years ago
4 0
1L ------------ 1 kg
? ------------- 3.8 kg

3.8 x 1 / 1

= 3.8 L
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3 years ago
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6 0
4 years ago
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Calculate the. number of moles of Cu. in 8.0×1021 atoms of Cu​
drek231 [11]

Answer:

8.0 × 10²¹ atoms contain 1.33 × 10⁻² moles.

Explanation:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen

Given data:

Number of atoms = 8.0 × 10²¹ atoms

Number of moles = ?

Solution:

One mole of Cu = 6.022 × 10²³ atoms

For 8.0 × 10²¹ atoms:

(1 mol / 6.022 × 10²³ atoms)×8.0 × 10²¹ atoms

1.33 × 10⁻² moles

So, 8.0 × 10²¹ atoms contain 1.33 × 10⁻² moles.

7 0
3 years ago
How many moles of h are in 0.73 mole of c6h10s
Mnenie [13.5K]

Answer:

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X= 0.73×10=7.3mole

7 0
3 years ago
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