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Shtirlitz [24]
3 years ago
10

A decomposition occurs when you open a can or bottle of soda. Carbonic acid. H.CO, is in carbonated beverages. It

Chemistry
1 answer:
Rina8888 [55]3 years ago
3 0

Answer:

H₂CO₃→H₂O + CO₂

Exphlanation:

Soda is carbonated water. It contains carbon dioxide dissolved in water , which is carbonic acid. On opening the soda, the carbonic acid undergoes the reverse reaction and releases carbon dioxide in the air . The soda is thus left with just water and loses it's fizz.

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igor_vitrenko [27]

Answer:

164

1st step we will write desperate molar mass of each element

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Bethany has a fish tank at her house. She uses the following data table to keep track of the nitrate and phosphate levels in the
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3 years ago
Read 2 more answers
One mole of an ideal gas with a volume of 1.0 L and a pressure of 5.0 atm is allowed to expand isothermally into an evacuated bu
Deffense [45]

Answer:

w= - 1.7173 kJ, q= 1.7173 kJ, q(rev) = 1717.3 J = 1.7173 kJ.

Explanation:

Okay, from the question we are given the information below;

Number of moles, n= 1 mole; initial volume, v(1) = 1.0 litres (L); pressure (p) = 5atm, final volume(v2) = 2.0 Litres(L) ; the workdone, w= not given; the heat, q and q(rev)= not given and the gas was said to expand isothermally.

So, this question is a question from the part of chemistry known as thermodynamics. Therefore, grip yourself we are delving into thermodynamics 'waters' now.

For expansion isothermally; the workdone, w= -nRT ln v2/v1.

Where T= temperature= 25° C = 298 k and R= gas constant.

Therefore; workdone, w = - 1 × 8.314 × 298 × ln(2/1).

Workdone,w= - 1717.32204643. =

- 1717.3 Joules (J).

==> Workdone,w= - 1.7173 kJ.

Then, we are to find q. q can be solved by using the first law of thermodynamics, which by mathematical representation is:

∆U= q + w. Where ∆U= change in internal enegy. Since the question is dealing with isothermal expansion, there is this rule that says for an isothermal expansion ∆U = 0.

Hence, 0 =q + [- 1717.3 Joules (J)].

q=1717.3 J = 1.7173 kJ.

Finally, the q(rev) which is= nRT ln (v2/V1).

q(rev) = 1 × 8.314 × 298 ln (2/1).

q(rev) = 1717.3 J = 1.7173 kJ.

PS: please note the negative signs in the workdone and the positive sign in the q(rev).

7 0
2 years ago
Which is generally stronger, intermolecular interactions or intramolecular interactions? Which is generally stronger, intermolec
Inessa [10]

Answer:

A. Intramolecular interactions are generally stronger.

B. a. Only intermolecular interactions are broken when a liquid is converted to a gas.

Explanation:

<em>A. Which is generally stronger, intermolecular interactions or intramolecular interactions?</em>

Intramolecular interactions, in which electrons are gained, lost or shared, constitute true bonds and are one or two orders of magnitude stronger than intermolecular interactions.

<em>B. Which of these kinds of interactions are broken when a liquid is converted to a gas?</em>

When a liquid vaporizes, the intermolecular attractions are broken, that is, molecules get more separated. However, true bonds are not broken which is why the molecules keep their chemical identity.

7 0
3 years ago
Directions: Use the words in the word box to complete the following sentences.
NeX [460]

Explanation:

When the forces acting on an object are balanced , there is no change in the object's motion.

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When a force acts in the opposite direction of another force, the forces counteract each other.

More than one force acting on a falling object can reduce its downward acceleration

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7 0
2 years ago
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