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3 years ago

2. As a pendulum swings, its energy is constantly converted between kinetic

Physics

1 answer:

Alex3 years ago

6 0

Answer:

at point F

Explanation:

To know the point in which the pendulum has the greatest potential energy you can assume that the zero reference of the gravitational energy (it is mandatory to define it) is at the bottom of the pendulum.

Then, when the pendulum reaches it maximum height in its motion the gravitational potential energy is

U = mgh

m: mass of the pendulum

g: gravitational constant

The greatest value is obtained when the pendulum reaches y=h

Furthermore, at this point the pendulum stops to come back in ts motion and then the speed is zero, and so, the kinetic energy (K=1/mv^2=0).

A) answer, at point F

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The following situation will be used for the next three problems: A rock is projected upward from the surface of the moon, at ti

chubhunter [2.5K]

Explanation:

Given that,

Initial speed of the rock, u = 30 m/s

The acceleration due to gravity at the surface of the moon is 1.62 m/s².

We need to find the time when the rock is ascending at a height of 180 m.

The rock is projected from the surface of the moon. The equation of motion in this case is given by :

$h=ut-\dfrac{1}{2}gt^2\\\\180=30t-\dfrac{1}{2}\times 1.62t^2$

It is a quadratic equation, after solving whose solution is given by:

t = 7.53 s

t = 8 seconds

(e)If it is decending, v = -20 m/s

Now t' is the time of descending. So,

$v=-u+gt\\\\t=\dfrac{v+u}{g}\\\\t=\dfrac{20+30}{1.62}\\\\t=30.86\ s$

Let h' is the height of the rock at this time. So,

$h'=ut-\dfrac{1}{2}gt^2\\\\h'=30\times 30.86-\dfrac{1}{2}\times 1.62\times 30.86^2\\\\h'=154.40\ m$

h' = 155 m

6 0

2 years ago

In t-ball, young players use a bat to hit a stationary ball off a stand. The 140 g ball has about the same mass as a baseball, b

fomenos

Question is missing. Found on google:

"Part A What is the acceleration of the ball? Express your answer to two significant figures and include the appropriate units.

Part B

What is the net force on the ball during the hit?

Express your answer to two significant figures and include the appropriate units."

Solution:

A) $6000 m/s^2$

The acceleration of the ball is given by

$a=\frac{v-u}{t}$

where

v = 12 m/s is the final velocity

u = 0 is the initial velocity (the ball is stationary)

t = 2.0 ms = 0.002 s is the time of contact

Substituting,

$a=\frac{12-0}{0.002}=6.0 \cdot 10^3 m/s^2$

B) $8.4\cdot 10^2 N$

The force on the ball can be found by using Newton's second law:

$F=ma$

where

m = 140 g = 0.14 kg is the mass of the ball

$a=6.0\cdot 10^3 m/s^2$ is the acceleration

Substituting,

$F=(0.14)(6.0\cdot 10^3)=8.4\cdot 10^2 N$

3 0

3 years ago

Please Help Quick ASAP Hurry This is Physical Science

krok68 [10]

Answer:

Think it is C

Explanation:

Not sure!!!

6 0

2 years ago

The diagram shows a stone suspended under the surface of a liquid from a string. The stone experiences a pressure caused by the

Ivan

Where is the diagram? What is the question?

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2 years ago

If a calorie is equivalent to 4.184 joules how many joules are contained in 250 kg calories slice of pizza

Andreyy89

In order to answer this, we will set up a simple ratio as such:

1 calorie = 4.184 joules

1 kilocalorie = 1000 calories

1 kilocalorie = 4,184 joules

250 kilocalories = x joules

Cross multiplying the second and third equations, we get:

x joules = 4,184 * 250

250 kilocalories are equivalent to 1,046 kJ

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2 years ago