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Alex73 [517]
3 years ago
6

2. As a pendulum swings, its energy is constantly converted between kinetic

Physics
1 answer:
Alex3 years ago
6 0

Answer:

at point F

Explanation:

To know the point in which the pendulum has the greatest potential energy you can assume that the zero reference of the gravitational energy (it is mandatory to define it) is at the bottom of the pendulum.

Then, when the pendulum reaches it maximum height in its motion the gravitational potential energy is

U = mgh

m: mass of the pendulum

g: gravitational constant

The greatest value is obtained when the pendulum reaches y=h

Furthermore, at this point the pendulum stops to come back in ts motion and then the speed is zero, and so, the kinetic energy (K=1/mv^2=0).

A) answer, at point F

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Absorbed solar radiation undergoes irreversible degradations, transferring from reservoir to another and ends up as what?
barxatty [35]

Answer:

Absorbed solar radiation undergoes irreversible degradations, transferring from reservoir to another converting from light energy to radiation energy.

Explanation:

The solar energy cycle functions in the following form:

  • Considering that 100% of energy is directed at earth.
  • When 100% light is incident on the Earth's surface about 6-7% of it is reflected back by the atmosphere into space.
  • 20% is reflected back by the clouds.
  • And about 4% is reflected back by Earth's surface.
  • 16% of solar energy is absorbed by the atmosphere, 3% is absorbed by clouds and 51% is absorbed by  land and ocean.
  • From the absorbed energy, 64% is radiated back to space from clouds and atmosphere and 6% is directly radiated back to space from earth.
  • From the radiated energy 15% is absorbed by the atmosphere and 23% is carried by the clouds and atmosphere through the latent heat in water vapor.

Therefore, absorbed solar radiation undergoes irreversible degradations, transferring from reservoir to another converting from light energy to radiation energy.

Learn more about solar energy here:

<u>brainly.com/question/18175736</u>

#SPJ4

6 0
2 years ago
The carpal bones in the hands are an example of __________.
Olenka [21]
The carpal bones in the hands are an example of __________.
Answer: gliding joints

<span>A gliding joint means a freely moving joint in which the articulations allow only gliding motions</span>
6 0
3 years ago
Read 2 more answers
(a) If your speedometer has an uncertainty of 2.0km/h at a speed of 90km/h, what is the percent uncertainty? (b) If it has the s
Airida [17]

Answer:

a) 2.22 %

b) Range would be 60±1.998 km/h

Explanation:

Percentage uncertainty indicates the error of a reading. With the percentage uncertainty error for a measurement can be calculated.

a) Percentage uncertainty would be

2\times \frac{100}{90}=2.22%

Percent uncertainty is 2.22%

b) For 60 km/h error would be

\frac{2.22}{100}\times 90=1.998

Range would be 60±1.998 km/h

6 0
4 years ago
Determine a valid way of finding the wire’s diameter if you know the resistivity of the material, \rho , and can measure the cur
olganol [36]

Answer:

To find the diameter of the wire, when the following are given:

Resistivity of the material (Rho), Current flowing in the conductor, I, Potential difference across the conductor ends, V, and length of the wire/conductor, L.

Using the ohm's law,

Resistance R = (rho*L)/A

R = V/I.

Crossectional area of the wire A = π*square of radius

Radius = sqrt(A/π)

Diameter = Radius/2 = [sqrt(A/π)]

Making A the subject of the formular

A = (rho* L* I)V.

From the result of A, Diameter can be determined using

Diameter = [sqrt(A/π)]/2. π is a constant with the value 22/7

Explanation:

Error and uncertainty can be measured varying the value of the parameters used and calculating different values of the diameters. Compare the values using standard deviation

7 0
3 years ago
A brand new corvette can go from 0 to 85 miles per hour in 4.8 seconds.
klasskru [66]

Answer:

(A) 7.9 m/s^{2}  

(B) 19 m/s

(C) 91 m

Explanation:

initial velocity (U) = 0 mph = 0 m/s

final velocity (V) = 85 mph = 85 x 0.447 = 38 m/s

initial time (ti) = 0 s

final time (t) = 4.8 s

(A) acceleration = \frac{V-U}{t}

         = \frac{38-0}{4.8} = 7.9 m/s^{2}  

(B) average velocity = \frac{V+U}{2}

     =\frac{38+0}{2} = 19 m/s

(C) distance travelled (S) = ut + 0.5at^{2}

  =  (0 x 4.8) + 0.5 x 7.9 x 4.8^{2} = 91 m

5 0
3 years ago
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