Answer:
6.25 L
Explanation:
Please see the step-by-step solution in the picture attached below.
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Answer:
OH−(aq), and H+(aq)
Explanation:
Redox reactions may occur in acidic or basic environments. Usually, if a reaction occurs in an acidic environment, hydrogen ions are shown as being part of the reaction system. For instance, in the reduction of the permanganate ion;
MnO4^-(aq) + 8H^+(aq) +5e-------> Mn^2+(aq) + 4H2O(l)
The appearance of hydrogen ion in the reaction equation implies that the process takes place under acidic reaction conditions.
For reactions that take place under basic conditions, the hydroxide ion is part of the reaction equation.
Hence hydrogen ion and hydroxide ion are included in redox reaction half equations depending on the conditions of the reaction whether acidic or basic.
First, we have to to whatever is in the parentheses:
(26 + 2)/7
(28)/7
Now solve:
28/7
4
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Answer:
THE MOLARITY OF SODIUM CHLORIDE IN THE CONTAINER IS 0.3846 M.
Explanation:
Molarity of a solution is the number of moles of solute per dm3 of solution.
Mass concentration = Molar concentration * Molar mass
1. calculate the mass concentration;
Mass conc. = 45 g in 2 L
= 45 g in 2 dm3
In 1 dm3, the mass will be 45 / 2
= 22.5 g/dm3 of NaCl.
2. Calculate the molar mass;
(Na = 23, Cl = 35.5)
Molar mass = ( 23 + 35.5 ) g/mol
Molar mass = 58.5 g/mol
3. calculate the molarity
Molarity = mss concentration / molar mass
Molarity = 22.5 g/dm3 / 58.5 g/mol
Molarity = 0.3846 mol/dm3 of NaCl.
The molarity of sodium chloride in the container is 0.3846 mol/dm3
The substances Oxygen and Hydrogen are elements.
