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pochemuha
3 years ago
5

If a 66.0-kg person stands with both feet on the same step, what is the gravitational potential energy of this person on the fir

st step of the flight of stairs relative to the same person standing at the bottom of the stairs?
Physics
1 answer:
Leokris [45]3 years ago
8 0

Answer:

U₁ = 129.4 J

Explanation:

The potential energy is

    U = mg y - m g y₀

Where I correspond to the initial position, with this it is an additive constant, we can make it zero with the placement of the reference system, in this case the system is placed on the floor where the ladder rests.

The power power for people on the floor is

     U₀ = 0 J

The potential energy for the person on the first step is

   U₁ = m g y₁

In general the steps are 20 cm high

     y₁ = 20 cm (1m / 100cm) = 0.20 m

     U₁ = 66 9.8 0.20

     U₁ = 129.4 J

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What is the mass number of a potassium atom that has 20 neutrons
posledela
 <span>The mass of potassium is 39. This is obtained by adding the 19 protons and 20 neutrons found inside the nucleus</span>


6 0
3 years ago
A 2800 kg speedboat starting from rest attains a speed of 16 m/s in 8.0 s as a combination of 1200 N of air resistance and water
denis23 [38]

Answer:

For me

Explanation:

power=workdone/time

power= 128×1200/8

power=19200

6 0
3 years ago
4. The Mariana trench is in the Pacific Ocean and has a depth of approximately 11,000 m. The density of seawater is approximatel
Alex73 [517]

Explanation:

It is known that relation between pressure and density is as follows.

            P = \rho gh

where,    P = pressure

     \rho = density

            g = acceleration due to gravity

            h = height

Putting the given values into the above formula as follows.

              P = \rho gh

                 = 1025 \times 9.8 \times 11000

                 = 110495000 Pa

Now, relation between pressure and force is as follows.

                P = \frac{F}{A}

or,            F = PA

                F = 110495000 \times \pi \times (0.1)^{2}

                   = 3.47 \times 10^{6} N

Thus, we can conclude that a force of 3.47 \times 10^{6} N can be  experienced at such depth.

3 0
3 years ago
If a bust starts to move and its velocity becomes 90 km after 8 seconds . calculate its acceleration answer it quick please
kherson [118]

Answer:

a = 3.125 [m/s^2]

Explanation:

In order to solve this problem, we must use the following equation of kinematics. But first, we have to convert the speed of 90 [km/h] to meters per second.

90\frac{km}{h}*\frac{1000m}{1km}*\frac{1h}{3600s}   \\= 25 \frac{m}{s}

v_{f} =v_{i} + (a*t)

where:

Vf = final velocity = 25 [m/s]

Vi = initial velocity = 0

a = acceleration [m/s^2]

t  = time = 8 [s]

The initial speed is zero as the bus starts to koverse from rest. The positive sign of the equation means that the bus increases its speed.

25 = 0 + a*8

a = 3.125 [m/s^2]

3 0
3 years ago
The SAF operates the M113 Ultra APC.
HACTEHA [7]

The volume of the object must be no larger than 11.15 m^3.

Explanation:

In order for an object to be able to float in water, its density must be equal or smaller than the water density.

The density of water is:

\rho = 1000 kg/m^3

This means that the density of the object must be no larger than this value.

We also know that the density of an object is given by

\rho = \frac{m}{V}

where

m is the mass of the object

V is its volume

For the object in this problem, the mass is

m=1.115\cdot 10^4 kg

Therefore, we can re-arrange the equation to find its volume:

V=\frac{m}{\rho}=\frac{1.115\cdot 10^4}{1000}=11.15 m^3

So, the volume of the object must be no larger than 11.15 m^3.

Learn more about density:

brainly.com/question/5055270

brainly.com/question/8441651

#LearnwithBrainly

8 0
3 years ago
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