Sylvia and Jadon now want to work a problem. Imagine a puck of mass 0.5 kg moving in a circular simulation. Suppose that the ten
1 answer:
Answer:
Tangential speed, v = 2.64 m/s
Explanation:
Given that,
Mass of the puck, m = 0.5 kg
Tension acting in the string, T = 3.5 N
Radius of the circular path, r = 1 m
To find,
The tangential speed of the puck.
Solution,
The centripetal force acting in the string is balanced by the tangential speed of the puck. The expression for the centripetal force is given by :
v = 2.64 m/s
Therefore, the tangential speed of the puck is 2.64 m/s.
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Answer:
899752.13598 N
Explanation:
p = Pressure on the plate =
A = Area =
F = Force on the region
When force is divided by area we get pressure
Force is exerted by the atmosphere on a disk-shaped region is 899752.13598 N
Answer:
The force felt by charge 3 is F=(-5.6*10⁻⁶,3.36⁻⁵)N
Explanation:
As the superposition principle applies to static charges, we can find the net electric force as the sum of the two forces felt by q3.
Looking at the drawing and knowing that they form an equilateral triangle of lenght 4 we can conclude that each internal angle is 60°.
So, the positions in our coordinate system are:
Now using Coulomb's force:
Where d=4, q1 = -7.8*10⁻⁹C, q2 = -15.6 *10⁻⁹C, q3 = 8.0 *10⁻⁹C, k=8.98*10⁹, e0=8.8*10¹⁰:
Replacing we get 2 equations:
To work with the sam
F=∑F_i=3.5*10⁻⁴(0.023,0.032)+7*10⁻⁴(-0.016,0.032)=
=((3.5*10⁻⁴-7*10⁻⁴)*0.016,(3.5*10⁻⁴+7*10⁻⁴)*0.032)=
F=(-5.6*10⁻⁶,3.36⁻⁵)N
