Answer:
(A) 10132.5Pa
(B)531kJ of energy
Explanation:
This is an isothermal process. Assuming ideal gas behaviour then the relation P1V1 = P2V2 holds.
Given
m = 10kg = 10000g, V1 = 0.1m³, V2 = 1.0m³
P1 = 101325Pa. M = 102.03g/mol
P2 = P1 × V1 /V2 = 101325 × 0.1 / 1 = 10132.5Pa
(B) Energy is transfered by the r134a in the form of thw work done in in expansion
W = nRTIn(V2/V1)
n = m / M = 10000/102.03 = 98.01mols
W = 98.01 × 8.314 × 283 ×ln(1.0/0.1)
= 531kJ.
Newton's Third Law of Motion states that for every action there must exist an equal but opposite reaction.
This ultimately implies that, Newton's Third Law of Motion is a law based on action-reaction force pairs.
In this exercise, you're required to identify the action-reaction forces in the attached picture.
Under condition A, a boy is leaning against a wall;
- The force being exerted by the boy on the wall is a force of action.
- The force being exerted by the wall on the boy is a force of reaction.
Under condition B, a boy is jumping off a diving board.
- The force being exerted by the feet of the boy on the diving board is a force of action.
- The force being exerted by the diving board on the feet of the boy is a force of reaction.
Under condition C, a nail is being hammered into the wall.
- The force being exerted by the hammer on the nail is a force of action.
- The force being exerted by the nail on the hammer is a force of reaction.
Under condition D, a man is walking on a ground (floor).
- The force being exerted by the foot of the man on the ground (floor) is a force of action.
- The force being exerted by the ground (floor) on the foot of the man is a force of reaction.
Under condition E, a boy is holding a ball;
- The force being exerted by the hand of the boy on the ball is a force of action.
- The force being exerted by the ball on the hand of the boy is a force of reaction.
Read more: brainly.com/question/15170643
Answer:
for the body to float, the density of the body must be less than or equal to the density of the liquid.
Explanation:
For a block to float in a liquid, the thrust of the liquid must be greater than or equal to the weight of the block.
Weight is
W = mg
let's use the concept of density
ρ_body = m / V
m = ρ_body V
W = ρ_body V g
The thrust of the body is given by Archimedes' law
B = ρ_liquid g V_liquid
as the body floats the submerged volume of the liquid is less than or equal to the volume of the block
ρ_body V g = ρ_liquid g V_liquid
ρ_body = ρ liquid Vliquido / V_body
As we can see, for the body to float, the density of the body must be less than or equal to the density of the liquid.
Thank you for posting your question here at brainly. Below is the solution:
E = (h * c) / λ
<span>E = h * f </span>
<span>E = (6.626E-34 J*s) * (6.00E14 Hz) </span>
<span>E = 397.5642E-21 Joules </span>
<span>E = 397.5642 zeptoJoules </span>
Answer:
the height of a object or point relation to sea level or ground level
