Answer:
The decay constant is 1.21×10^-4/year
Explanation:
Decay constant = 0.693/half-life
Half-life = 5730 years
Decay constant = 0.693/5730 years = 1.21×10^-4/year
Answer: Fr = 26.53 N
Explanation: The constant force exerted on the block by the surface is the frictional force.
This frictional force is as a result of interaction between the body and the surface.
According to newton's second law of motion,
F - Fr = ma
F=applied force
Fr = magnitude of frictional force
m = mass of object = 12kg
a = acceleration of object = 3.2m/s²
The applied force (F= 75 N) is inclined at an angle of 30° to the horizontal thus making it have 2 components of forces given below
Fx = 75 * cos 30 = 64.95 N (horizontal component)
Fy = 75 * sin 30 = 37.5 N ( vertical motion)
The body moves across the surface, hence the horizontal component of force is responsible for motion.
F = 64.95 N
By substituting the parameters, we have that
64.96 - Fr = 12 * 3.2
64.96 - Fr = 38.4
Fr = 64.96 - 38.4
Fr = 26.53 N
A) Water freezing
This is called the process of turning water as a liquid to its solid form which is ice.
Ice is almost together as one unlike liquid. This is why the molecules are more orderly.
The process of freezing is exothermic which means the heat has to be removed in the process.
Answer: F = 776.18N θ = 29.41°
Question:
The magnitude of the resultant force is to be 200 N, directed along the positive y-axis. Determine the magnitude of the force F Find the angle θ.
Attached is the image.
Explanation:
To solve this question we need to resolve the forces to the x and y axis.
For the x axis;
Fcosθ = 700cos15....1
For the y axis;
200 = Fsinθ - 700sin15
Fsinθ = 200 + 700sin15 ...2
Dividing equation 2 by 1
Fsinθ/Fcosθ = (200 + 700sin15)/700cos15
Tanθ = (200 + 700sin15)/700cos15
θ = Taninverse(200 + 700sin15)/700cos15)
θ = 29.41°
From equation 1;
F = 700cos15/cosθ
F = 700cos15/cos29.41
F = 776.18N
