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My name is Ann [436]
4 years ago
3

Which best describes the relationship between internal energy and thermal energy? Thermal energy is a measure of the internal en

ergy of a substance. Internal energy is a measure of the thermal energy of a substance. Internal energy is the portion of thermal energy that can be transferred. Thermal energy is the portion of internal energy that can be transferred.
Physics
2 answers:
NISA [10]4 years ago
8 0

Answer:

Thermal energy is the part of internal energy that is capable of being transferred to other objects.

Explanation:

Thermal energy is capable of being transferred until the objects become the same temperature, called equilibrium.

sdas [7]4 years ago
4 0

Thermal energy is the portion of internal energy that can be transferred.

Explanation:

The statement that best describes and defines the relationship between thermal energy and internal energy is that, thermal energy is a portion of the internal energy that can be transferred.

The internal energy of a system is the sum of all the kinetic and potential energy of a system.

   Internal energy = potential energy + kinetic energy

  • Kinetic energy is due to the motion of the particles of a medium.
  • One form of kinetic energy in particles is thermal energy.
  • Thermal energy is the form of internal energy that can be transferred as a result of temperature differences between two bodies.
  • Thermal energy is transferred as heat.

learn more:

Thermal energy brainly.com/question/914750

#learnwithBrainly

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Define gravitational force in your own words.
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The specific heat of soil is 0.20 kcal/kg*C and the specific heat of water is 1.00 kcal/kg*C. This means that if 1 kg of soil an
stiv31 [10]

Answer: The soil will be 4\°C warmer than the water.

Explanation:

The heat (thermal energy) absorbed can be found using the following equation:

Q=m.C.\Delta T

Where:

Q is the heat  

m is the mass of the element

C is the specific heat capacity of the material.

\Delta T is the variation in temperature

<u>In the case of soil we have:</u>

Q_{soil}=m_{soil}.C_{soil}.\Delta T_{soil} (1)

Where:

Q_{soil}=1 kcal

m_{soil}=1 kg

C_{soil}=0.2 kcal/kg \°C

\Delta T_{soil}

<u>In the case of water we have:</u>

Q_{water}=m_{water}.C_{water}.\Delta T_{water} (2)

Where:

Q_{water}=1 kcal

m_{water}=1 kg

C_{water}=1 kcal/kg \°C

\Delta T_{water}

Isolating \Delta T from both equations:

\Delta T_{soil}=\frac{Q_{soil}}{m_{soil}.C_{soil}} (3)

\Delta T_{soil}=\frac{1 kcal}{1 kg(0.2 kcal/kg \°C)}

\Delta T_{soil}=5\°C (4)

\Delta T_{water}=\frac{Q_{water}}{m_{water}.C_{water}} (5)

\Delta T_{water}=\frac{1 kcal}{1 kg(1 kcal/kg \°C)}

\Delta T_{water}=1\°C (6)

Comparing (4) and (6) we can find the soil will be 4\°C warmer than the water.

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