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Leviafan [203]
2 years ago
6

Write balanced complete ionic equation for MgS(aq)+CuCl2(aq) = CuS(s)+MgCl2(aq)

Chemistry
2 answers:
oee [108]2 years ago
8 0
<span>The balanced chemical ionic equarion of MgS(aq)+CuCl2(aq) = CuS(s)+MgCl2(aq) would be as follows:

</span><span>Mg2+ + S2- + Cu 2+ + 2 Cl- ==> CuS + Mg2+ + 2 Cl-

Therefore, the net equation would be:

</span><span>Cu 2+ + S 2-  ===> CuS 
</span><span>
Hope this helps.


</span>
Aleks [24]2 years ago
6 0

Answer : The net ionic equation will be,

S^{2-}(aq)+Cu^{2+}(aq)\rightarrow CuS(s)

Explanation :

In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

The given balanced ionic equation will be,

MgS(aq)+CuCl_2(aq)\rightarrow CuS(s)+MgCl_2(aq)

The ionic equation in separated aqueous solution will be,

Mg^{2+}(aq)+S^{2-}(aq)+Cu^{2+}(aq)+2Cl^-(aq)\rightarrow CuS(s)+Mg^{2+}(aq)+2Cl^-(aq)

In this equation, Mg^{2+}\text{ and }Cl^- are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

S^{2-}(aq)+Cu^{2+}(aq)\rightarrow CuS(s)

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Here, we have the initial concentration (<em>M</em>₁) and the initial (<em>V</em>₁) and final (<em>V</em>₂) volumes, and we want to find the final concentration (<em>M</em>₂), or the concentration of the solution after dilution. So, we can rearrange our equation to solve for <em>M</em>₂:

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