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MAXImum [283]
3 years ago
8

Compute the equilibrium constant at 25 ∘C for the reaction between Sn2+(aq) and Cd(s), which form Sn(s) and Cd2+(aq). Express yo

ur answer using two significant figures
Chemistry
1 answer:
Radda [10]3 years ago
8 0

Answer:

6.1×10^8

Explanation:

The reaction is;

Sn^2+(aq) + Cd(s) -----> Sn(s) + Cd^2+(aq)

E°cell = E°cathode - E°anode

E°cathode= -0.14 V

E°anode= -0.40 V

E°cell = -0.14-(-0.40)

E°cell= -0.14+0.40

E°cell= 0.26 V

But

E°cell= 0.0592/n log K

E°cell= 0.0592/2 log K

0.26= 0.0296log K

log K = 0.26/0.0296

log K= 8.7838

K= Antilog (8.7838)

K= 6.1×10^8

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How many moles of Ca are in 7.2x10^25 molecules of Ca<br> (show work)
Gre4nikov [31]

Answer:

<h2>119.60 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{7.2 \times  {10}^{25} }{6.02 \times  {10}^{23} }   \\  =119.60132...

We have the final answer as

<h3>119.60 moles</h3>

Hope this helps you

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