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vazorg [7]
4 years ago
9

Need help !!!!! ASAP

Chemistry
1 answer:
gavmur [86]4 years ago
7 0
<h2>Hello!</h2>

The answer is:

The new temperature will be equal to 4 K.

T_{2}=4K

<h2>Why?</h2>

We are given the volume, the first temperature and the new volume after the gas is compressed. To calculate the new temperature after the gas was compressed, we need to use Charles's Law.

Charles's Law establishes a relationship between the volume and the temperature at a gas while its pressure is constant.

Now, to calculate the new temperature we need to assume that the pressure is kept constant, otherwise, the problem would not have a solution.

From Charle's Law, we have:

\frac{V_{1}}{T_{1}}=\frac{V_{2}}{T_{2}}

So, we are given the following information:

V_{1}=500mL\\T_{1}=20K\\V_{2}=100mL

Then, isolating the new temperature and substituting the given information, we have:

\frac{V_{1}}{T_{1}}=\frac{V_{2}}{T_{2}}

T_{2}=\frac{T_{1}}{V_{1}}*V_{2} \\

T_{2}=\frac{20.00K}{500mL}*100mL\\

T_{2}=4K

Hence, the new temperature will be equal to 4 K.

T_{2}=4K

Have a nice day!

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I. Kindly, see the attached image.

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III. - 51.88 kJ/mol.

IV. The reaction is spontaneous.

Explanation:

I. Draw a possible potential energy diagram of the reaction. Label the enthalpy of the reaction.

  • Since the sign of ΔH is negative, the reaction is exothermic reaction.

In an exothermic reaction, the energy of the reactants is higher than that of the products.

<u><em>Kindly see the attached image to show you the potential energy diagram of the reaction.</em></u>

     

<em>II. Is the reaction endothermic or exothermic? Explain your answer.</em>

  • The reaction is exothermic reaction.
  • The sign of ΔH indicates wither the reaction is endothermic or exothermic one:

If the sign is positive, the reaction is endothermic.

If the sign is negative, the reaction is exothermic.

Herein, <em>ΔH = - 33.1 kJ/mol, </em>so the reaction is exothermic.

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∵ ΔG = ΔH - TΔS.

Where, ΔG is the Gibbs free energy change (J/mol).

ΔH is the enthalpy change (ΔH = - 33.1 kJ/mol).

T is the temperature (T = 25°C + 273 = 298 K).

ΔS is the entorpy change (ΔS = 63.02 J/mol.K = 0.06302 J/mol.K).

<em>∴ ΔG = ΔH - TΔS</em> = (- 33.1 kJ/mol) - (298 K)(0.06302 J/mol.K) = <em>- 51.88 kJ/mol.</em>

IV. Is the reaction spontaneous or nonspontaneous at 25°C?

The sign of ΔG indicates the spontaneity of the reaction:

If ΔG < 0, the reaction is spontaneous.

If ΔG = 0, the reaction is at equilibrium.

If ΔG > 0, the reaction is nonspontaneous.

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