Answer:
Heat of vaporization will be 22.59 j
Explanation:
We have given mass m = 10 gram
And heat of vaporization L = 2.259 J/gram
We have to find the heat required to vaporize 10 gram mass
We know that heat of vaporization is given by
, here m is mass and L is latent heat of vaporization.
So heat of vaporization Q will be = 10×2.259 = 22.59 J
This correct answer would be C
The period of a simple pendulum is given by:

where L is the length of the pendulum and

is the gravitational acceleration. As we can see, the period of a simple pendulum depends only on its length.
Answer:
4 m
Explanation:
From the question given above, the following data were obtained:
Initial velocity (u) = 10 m/s
Acceleration (a) = –8m/s²
Time (t) = 2 s
Displacement (s) =?
The displacement of the object can be obtained as follow:
s = ut + ½at²
s = (10 × 2) + (½ × –8 × 2²)
s = 20 + (–4 × 4)
s = 20 + (–16)
s = 20 – 16
s = 4 m
Thus, the displacement of the object is 4 m.