All categories

2 years ago

Which operation involving complex numbers requires the use of a conjugate to be carried out?

Mathematics

1 answer:

Pani-rosa [81]2 years ago

3 0

Answer:

The correct answer will be "Division".

Step-by-step explanation:

The procedure represents numerous values requiring something like a conjugate to have been done becomes division, since the denominator conjugate multiplies the numeric values including its quotient to represent the quotient of several complex numbers throughout the standard language.
It is indeed a method used to separate a set of items across equal proportions.

You might be interested in

What is the value of the expression i 0 × i 1 × i 2 × i 3 × i 4?

astraxan [27]

ANSWER

The value of the expression is
$- 1$

EXPLANATION

Method 1: Rewrite as product of
${i}^{2}$

The expression given to us is,

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4}$

We use the fact that
${i}^{2} = - 1$
to simplify the above expression.

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = {i}^{0} \times {i}^{1} \times {i}^{3} \times {i}^{2} \times {i}^{4}$

This implies,

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = {i}^{0} \times {i}^{2} \times {i}^{2} \times {i}^{2} \times {i}^{2} \times {i}^{2}$

We substitute to obtain,

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = 1\times - 1 \times - 1 \times - 1\times - 1 \times - 1$

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = 1\times 1 \times 1 \times - 1 = - 1$

Method 2: Use indices to solve.

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = {i}^{0 + 1 + 2 + 3 + 4}$

This implies that,

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = {i}^{10}$

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = ( {{i}^{2}} )^{5}$

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = ( - 1 )^{5} = - 1$

8 0

3 years ago

Read 2 more answers

Help please 17 points!!

Darina [25.2K]

Answer:

I dont really do this kind of work but i think its A

Step-by-step explanation:

3 0

2 years ago

What is the solution to the equation -√(15+x)=-3?

marin [14]

So, the negative would be divided out to make it 3, then square both sides to get rid of the square root and get 9, then subtract 15 and you get -6. <span />

7 0

2 years ago

Read 2 more answers

Polygon HJKL has vertices H(-3, 4), J(2, 6), K(2, 1), and L(-3, -1). What are the slopes of sides HJ, JK, KL, and LH and how wou

aleksklad [387]

<span> the slopes of sides HJ, JK, KL, and LH and how would you classify HJKL?</span>

4 0

2 years ago

Reduce -3/-3 hurrry please.

Darya [45]

Answer:

=>1

=> $\frac{-3}{-3}$

=> Simplify:minus and minus simplify each other and so do 3 and 3

=> So were are left with 1

Thus,the answer is 1

Step-by-step explanation:

5 0

2 years ago

Which operation involving complex numbers requires the use of a conjugate to be carried​ out?

Which operation involving complex numbers requires the use of a conjugate to be carried out?