1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
bekas [8.4K]
3 years ago
13

What is the pressure of the gas in this mercury manometer if h = 89 mm and atmospheric pressure is 775 mmhg?

Physics
2 answers:
ludmilkaskok [199]3 years ago
6 0
The pressure of the gas is 686 mmhg.
If h = 89 mm
and atmospheric pressure = 775 mmhg
Pressure of the gas = ?
We can find the pressure of the gas by finding the difference between both values.
pressure of the gas = 775 mmhg - 89 mm = 686 mmhg
aleksandr82 [10.1K]3 years ago
3 0

The pressure of the gas in this mercury manometer ( Figure 1 ) is about 864 mmHg

\texttt{ }

<h3>Further explanation</h3>

The basic formula of pressure that needs to be recalled is:

Pressure = Force / Cross-sectional Area

or symbolized:

\large {\boxed {P = F \div A} }

<em>P = Pressure (Pa)</em>

<em>F = Force (N)</em>

<em>A = Cross-sectional Area (m²)</em>

Let us now tackle the problem !

\texttt{ }

In this problem , we will use Ideal Gas Law as follows:

<u>Given:</u>

height of mercury column = h = 89 mm

atmospheric pressure = Po = 775 mmHg

<u>Asked:</u>

the pressure of the gas = P = ?

<u>Solution:</u>

We will use Hydrostatic Pressure formula to solve this problem as follows:

P = Po + \rho g h

P = 775 \texttt{ mmHg} + 89 \texttt{ mmHg}

P = 864 \texttt{ mmHg}

\texttt{ }

<h3>Conclusion :</h3>

The pressure of the gas in this mercury manometer ( Figure 1 ) is about 864 mmHg

\texttt{ }

<h3>Learn more</h3>
  • Minimum Coefficient of Static Friction : brainly.com/question/5884009
  • The Pressure In A Sealed Plastic Container : brainly.com/question/10209135
  • Effect of Earth’s Gravity on Objects : brainly.com/question/8844454

\texttt{ }

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Pressure

You might be interested in
Which of the following would result if thermal energy is added to an object?​
seropon [69]

Answer:

is there supposed to be a pic and abcd options?

8 0
3 years ago
How could you group pennies,nickels, and dimes together
julsineya [31]

There isn't a direct answer to this, but I can show you!

This is how you group Pennies, Nickels, and Dimes.

1 Penny= 1 cent.

1 Nickel= 5 cents.

1 Dime= 10 cents.

Imagine if there was 5 pennies, 3 dimes, and 8 Nickels.

That might seem like a lot of numbers, but it's pretty simple!

You know how pennies are worth 1 cent? If we had 5 pennies, that would be 5 cents.

1+1+1+1+1=5 cents.

Then, we have 3 dimes. Dimes are each 10 cents.

So, 10x3 (If you know multiplication,  if not, you will learn it later) :)

10+10+10=  30 cents.

Now, nickels. We have 8 nickels! Remember, each nickel is 5 cents.

5+5+5+5+5+5+5+5=

40 Nickels.

Now add all of the coins up.

5 cents + 30 cents + 40 cents = 75 cents!

I hope this helped! If you need more help, you can ask me. :)

5 0
3 years ago
State ohm’s law Q.34.7
defon

Ohm's law states that: V=RI

Explanation:

Ohm's law states that in a conductor, the potential difference across the conductor is directly proportional to the current flowing through it. Mathematically,

V \propto I

where

V is the potential difference

I is the current

The constant of proportionality is called resistance (R), and it gives a measure of "how much the conductor opposes" to the flow of current. Therefore Ohm's law can be rewritten as

V=RI

where R is the resistance. By rewriting the equation as

I=\frac{V}{R}

we see that the larger the resistance, the lower the current in the conductor.

Learn more about Ohm's law:

brainly.com/question/4438943

brainly.com/question/10597501

brainly.com/question/12246020

#LearnwithBrainly

4 0
3 years ago
How would the period of a simple pendulum be affected if it were located on the moon instead of the earth?
OlgaM077 [116]

Answer:

On moon time period will become 2.45 times of the time period on earth

Explanation:

Time period of simple pendulum is equal to T=2\pi \sqrt{\frac{l}{g}} ....eqn 1 here l is length of the pendulum and g is acceleration due to gravity on earth

As when we go to moon, acceleration due to gravity on moon is \frac{1}{6} times os acceleration due to gravity on earth

So time period of pendulum on moon is equal to

T_{moon}=2\pi \sqrt{\frac{l}{\frac{g}{6}}}=2\pi \sqrt{\frac{6l}{g}} --------eqn 2

Dividing eqn 2 by eqn 1

\frac{T_{moon}}{T}=\sqrt{\frac{6l}{g}\times \frac{g}{l}}

T_{moon}=\sqrt{6}T=2.45T

So on moon time period will become 2.45 times of the time period on earth

5 0
3 years ago
Miss Hu taught her class what makes night and day on Earth. She could not use the real Sun. She used a light bulb instead. In th
kherson [118]

B. model; it is the model of the sun

5 0
3 years ago
Read 2 more answers
Other questions:
  • Which question would most likely fill in the blank
    6·1 answer
  • The tides on earth are caused mainly by earths gravitational interactions with which of the following?
    6·1 answer
  • If you have charged an electroscope by contact with a positively charged object, describe how you could use it to determine the
    13·1 answer
  • A truck with 0.420-m-radius tires travels at 32.0 m/s. what is the angular velocity of the rotating tires in radians per second?
    9·1 answer
  • Object 1 of mass m moves with speed v in the positive direction. Object 2 of mass 3 m moves with speed 4 v in the negative x-dir
    15·1 answer
  • If a fuse melts, does it create an open circuit, a closed circuit, or a short circuit?
    15·2 answers
  • How can you determine that a coin
    14·1 answer
  • 26. Keenan found the mass of a book to be 4.56*10^ -2 kg . What is the mass of the book in milligrams?​
    14·1 answer
  • In 1656, the Burgmeister (mayor) of the town of Magdeburg, Germany, Otto Von Guericke, carried out a dramatic demonstration of t
    6·1 answer
  • Which has zero acceleration?
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!