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2 years ago

Part Two: Criteria, Constraints, and Prioritizations

Physics

1 answer:

AlexFokin [52]2 years ago

7 0

Answer:

Usually, a solution can have several criteria and constraints. Even though all are important, some criteria are more important than others. The same holds true for constraints. But what do you do if it's impossible for a solution to cover every criterion while avoiding every constraint? In cases like this, you can use prioritization. Listing criteria and constraints based on priority shows the relative importance of each. You will need to prioritize the criteria and constraints for each sub-problem so that you can design a solution for each one individually. Prioritization can help you compare two different possible solutions. For example, the criterion that cars travel at 15 mph through the neighborhood might be a higher priority than the constraint that homeowners are only willing to spend $10,000 on this issue. If this is the case, you would want to generate solutions that also follow the priority in mind. All criteria are important, but engineers must sometimes make a trade-off, which is a compromise or change in one or more criteria or constraints so that they can be met at the same time. This is where prioritization comes in handy as it helps determine the trade-offs. A solution that is doing a better job of meeting one criterion may result in not completely meeting another criterion. Prioritization will help you choose which solution to go with.

Explanation:

I got this from quizlet :)

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Answer and mark you as brainliest <br> it's that easy

Oduvanchick [21]

Answer:

$t=\frac{v-u}{a}$

b) 35m/s

c) 0

d) -35m/s

e) Velocity is decreasing.

f) 70 seconds

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3 years ago

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A merry-go-round on a playground consists of a horizontal solid disk with a weight of 805 N and a radius of 1.58 m. A child appl

lozanna [386]

Answer:

The value is $KE = 259.6 \ J$

Explanation:

From the question we are told that

The weight of the horizontal solid disk is $W = 805 \ N$

The radius of the horizontal solid disk is $r = 1.58 \ m$

The force applied by the child is $F = 49.5 \ N$

The time considered is $t = 2.95 \ s$

Generally the mass of the horizontal solid disk is mathematically represented as

$m_h = \frac{W}{ g}$

=> $m_h = \frac{805}{ 9.8 }$

=> $m_h = 82.14 \ N$

Generally the moment of inertia of the horizontal solid disk is mathematically represented as

$I = \frac{1}{2} * m * r^ 2$

=> $I = \frac{1}{2} * 82.14 * 1.58^ 2$

=> $I = 102.5 \ kg \cdot m^2$

Generally the net torque experienced by the horizontal solid disk is mathematically represented as

$T = I * \alpha = F * r$

=> $\alpha = \frac{ F * r }{ I }$

=> $\alpha = \frac{ 49.5 * 1.58 }{ 102.53 }$

=> $\alpha = 0.7628$

Gnerally from kinematic equation we have that

$w = w_o + \alpha t$

Here $w_o$ is the initial angular velocity velocity of the horizontal solid disk which is $w_o = 0\ rad/s$

$w = 0 + 0.7628 * 2.95$

=> $w = 2.2503 \ rad/s$

Generally the kinetic energy is mathematically represented as

$KE = \frac{1}{2} * I * w^2$

=> $KE = \frac{1}{2} * 102.53 * 2.2503 ^2$

=> $KE = 259.6 \ J$

8 0

2 years ago

Matching

Anon25 [30]

Answer:

D. Principle of original horizontality

B. Principle of faunal succession

A. Uniformitarianism

C. Principle of superposition

Explanation:

Question 1

The principle of original horizontality is one of the foremost relative dating principle that is wide used in stratigraphy.

It states that "sedimentary rocks are laid down flatly on top one another in a sedimentary basin".

Sedimentary rocks will only vary vertically, but laterally, they are uniform and internally homogeneous in space. This is why most sedimentary rocks are stratified and laid layers upon layers just like the pages of a book.

Each layer is called a bed and often times are laterally continuous in space within the same basin.

Whenever we see beds not horizontally continuous, we can conclude that a tectonic event must have disrupted the sequence and it came after the it was formed.

Question 2

Principle of faunal succession succession was proposed by Williams Smith, an English Geologist and a canal worker in the 19th century.

Based on this principle, sedimentary rocks can placed in their proper chronostratigrahic framework based on the fossils they contain in them.

This principle is hinged on theory of evolution.
It is widely accepted that organisms evolved from one another.
Rocks often bear these records in fossil remains and this can help us appropriately fit rocks to the time they were formed.

Question 3

The principle of uniformitarianism was one of the disruptive proposition in earth science.

A Scottish name James Hutton while in the country side made this proposition as he observed how landform in his native changed with each episode of season.

The principle proposes that "the processes occurring today have occurred in the time past at the same rate".

This way, it was much more easier to understand how land changes in pre-historic times have occurred.

Before his theory, the principle of catastrophism was the widely accepted one. This theory suggested that events occurred rapidly and changes to the surface are much more faster.

Question 4

The principle of superposition is one of the relative dating principles. It proposes that "in an undeformed land sequence, the oldest rock is at the bottom and the youngest on top".

The first sediment to get deposited fills the bottom as it aggregates upward. This leaves the youngest lithology to the top of strata.

The principle is correct for undeformed or undisturbed rock strata.

Where the sediments are disturbed, the formation might be overturned and this principle might be difficult to apply.

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3 years ago

Oceanic crust is much denser than continental crust

Free_Kalibri [48]

Oceanic because it’s denser

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2 years ago

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Sam is recklessly driving 60 mph in a 30 mph speed zone when he suddenly sees the police. he steps on the brakes and slows to 30

barxatty [35]

For this problem, we use the derived equations for rectilinear motion at constant acceleration. The equations used for this problem are:

a = (v - v₀)/t
2ax = v² - v₀²
where
a is the acceleration
x is the distance
v is the final velocity
v₀ is the initial velocity
t is the time

The solution is as follows;

a = (60mph - 30 mph)/(3 s * 1 h/3600 s)
a = 36,000 mph²

2(36,000 mph²)(x) = 60² - 30²
Solving for x,
x = 0.0375 miles

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2 years ago