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Yuliya22 [10]
2 years ago
5

What is the potential drop across R3? (R1 = 20 Ω, R2 = 40 Ω, R3= 60 Ω, V = 60 V) (Ohm's law: V = IR)

Physics
1 answer:
Licemer1 [7]2 years ago
7 0
Correct answer: Option D. 30 V

The resistors are connect in series, because in parallel the potential drop across all resistors will have been the same and will be equal to the battery voltage i.e. 60 V.

First we need to find the equivalent resistance and the current passing through the circuit.

Since, resistors are in series, equivalent resistance will be the sum of all individual resistances. So,

Equivalent Resistance = 20 + 40 + 60 = 120 ohm
Current through the circuit = Voltage / Equivalent Resistance  = 60/120 = 0.5 ampere

The voltage drop across R3 =Resistance of R3 x Current 
= 60 x 0.5
= 30 V

Therefore, D option is the correct answer.
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The stoplights on a street are designed to keep traffic moving at 26 mi/h. the average length of a street block between traffic ligh
bonufazy [111]

We use the formula,

v = \frac{d}{t}.

Here, v is velocity and its value given 26 mi/h ( in m/s,  \frac{26 \times 1.609 \times 10^{3} m}{60 \times 60 s} =11.62 \ m/s ) and d is distance and its value is given 80 m.

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2 years ago
How much power is required to lift a 60 kg bed to the top of a 3 meter flight of stairs in 10 seconds?
Zigmanuir [339]

Answer:

176.58Watts

Explanation:

Power= work done /time

Where mass(m)=60kg

Height (h) =3m

Time(s)=10s

Force of gravity = 9.81m/s^2

Power=mgh/t

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8 0
3 years ago
How does the size of arctic foxes ears help to keep them warm in a cold environment
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3 years ago
A car is driving away from a crosswalk. The formula d = t 2 + 2 t expresses the car's distance from the crosswalk in feet, d , i
Ede4ka [16]

Answer:

1) No, the car does not travel at constant speed.

2) V = 9 ft/s

3) No, the car does not travel at constant speed.

4) V = 5.9 ft/s

Explanation:

In order to know if the car is traveling at constant speed we need to derive the given formula. That way we get speed as a function of time:

V(t) = 2*t + 2   Since the speed depends on time, the speed is not constant at any time.

For the average speed we evaluate the formula for t=2 and t=5:

d(2) = 8 ft     and      d(5) = 35 ft

V_{2-5}=\frac{d(5)-d(2)}{5-2}=9 ft/s

Again, for the average speed we evaluate the formula for t=1.8 and t=2.1:

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V_{1.8-2.1}=\frac{d(2.1)-d(1.8)}{2.1-1.8}=5.9 ft/s

4 0
3 years ago
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