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ivann1987 [24]
3 years ago
7

The sulfur atom of sulfur dioxide is considered to be sp2-hybridized. The expected bond angle is 120°, but is actually slightly

smaller (119°). Write down the correct statement that explains the smaller bond angle.

Chemistry
1 answer:
Alja [10]3 years ago
6 0

Answer: The bonds are intermediate between double and single bonds

Explanation:

A closer look at the diagram below shows that the bonds in sulphur IV oxide are intermediate between double and single bonds. Hence they do not have the exact bond angle of single bonds. This is why the bond angle is not exactly 120°. There are two resonance structures in the diagram that clearly show this point.

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Which of the following values would you expect for the ratio of half-lives for a reaction with starting concentrations of 0.05M
harkovskaia [24]

Answer:

The expected ratio of half-lives for a reaction will be 5:1.

Explanation:

Integrated rate law  for zero order kinetics is given as:

k=\frac{1}{t}([A_o]-[A])

[A_o] = initial concentration

[A]=concentration at time t

k = rate constant

if, [A]=\frac{1}{2}[A_o]

t=t_{\frac{1}{2}}, the equation (1) becomes:

t_{\frac{1}{2}}=\frac{[A_o]}{2k}

Half life when concentration was 0.05 M=t_{\frac{1}{2}}

Half life when concentration was 0.01 M=t_{\frac{1}{2}}'

Ratio of half-lives will be:

\frac{t_{\frac{1}{2}}}{t_{\frac{1}{2}}'}=\frac{\frac{[0.05 M]}{2k}}{\frac{[0.01 M]}{2k}}=\frac{5}{1}

The expected ratio of half-lives for a reaction will be 5:1.

6 0
3 years ago
Use the image to answer the question.
liberstina [14]

Answer:b

Explanation: it’s in the picture just go counterclockwise

7 0
3 years ago
Read 2 more answers
Balancing equations <br><br> H2SO4 +<br> NaOH<br> Na2SO4 +<br> H20
notsponge [240]

Explanation:

<h3>H2SO4 + 2 NaOH = Na2SO4 + 2H20, </h3>

<h3>2 in sodium hydroxide </h3><h3>And 2 in water </h3>
6 0
3 years ago
Cu + 2 AgNO3 + Cu(NO3)2 + 2Ag
Allushta [10]

Answer:

7.28 moles Ag°

Explanation:

              Cu°          +    2 AgNO₃  => Cu(NO₃)₂ + 2Ag°

Given 7.28 moles     7.28 moles

To determine limiting reactant, divide the mole values by the respective coefficient of balanced equation. The resulting smallest value is the limiting reactant. Note: this is a short cut method for determining limiting reactant only. Once the limiting reactant is determined one must use the given mole values of the limiting reactant to solve problem. That is ...

Limiting reactant determination:

              Cu°          +    2 AgNO₃  => Cu(NO₃)₂ + 2Ag°

Cu: 7.28 / 1  = 7.28

AgNO₃ : 7.28 / 2 = 3.64 => Limiting Reactant is AgNO₃

Solving Problem depends on AgNO₃; Cu will be in excess.

Since coefficients of AgNO₃ & Ag° are equal, then the moles AgNO₃ used equals moles Ag° produced and is therefore 7.28 moles Ag°.

5 0
3 years ago
QUESTION 5
Gnom [1K]

Answer:

They are organic

6 0
3 years ago
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