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ololo11 [35]
3 years ago
5

If you were standing under a tree, which object would appear to move?

Physics
2 answers:
kherson [118]3 years ago
6 0
B. the plane because it is flying and passing through
Stels [109]3 years ago
4 0
The tree should move because the wind will blow it
I'm not really sure
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Relative density, or specific gravity, is the ratio of the density of a substance to the density of a given reference material. Specific gravity for liquids is nearly always measured with respect to water at its densest; for gases, the reference is air at room temperature.
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You are discussing a material that has a strong resistance to the flow of electrons. This is a description of a(n)
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Can someone help me with this question
monitta

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hypothesis , hope it helps

Explanation:

7 0
3 years ago
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Two loudspeakers in a 20c room emit 686 hz sound waves along the x-axis.a. if the speakers are in phase, what is the smallest di
jeyben [28]

<u>Answer :</u>

(a) d = 0.25 m

(b) d = 0.5 m

<u>Explanation :</u>

It is given that,

Frequency of sound waves, f = 686 Hz

Speed of sound wave at 20^0\ C is, v = 343 m/s

(1) Perfectly destructive interference occurs when the path difference is half integral multiple of wavelength i.e.

d=\dfrac{\lambda}{2}........(1)

Velocity of sound wave is given by :

v=f\times \lambda

d=\dfrac{v}{2f}

d=\dfrac{343\ m/s}{2\times 686\ Hz}

d=0.25\ m

Hence, when the speakers are in phase the smallest distance between the speakers for which the interference of the sound waves is perfectly destructive is 0.25 m.

(2) For constructive interference, the path difference is integral multiple of wavelengths i.e.

d=n\lambda  ( n = integers )

Let n = 1

So, d=\dfrac{v}{f}

d=\dfrac{343\ m/s}{686\ Hz}

d=0.5\ m

Hence, the smallest distance between the speakers for which the interference of the sound waves is maximum constructive is 0.5 m.

4 0
3 years ago
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20 POINTSSS!!!!!!!!
Soloha48 [4]
Answer: A
Hope this help you!!
7 0
3 years ago
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