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Firdavs [7]
3 years ago
12

A certain reaction has the form aA → bB. At a particular temperature and [A]0 = 2.80 × 10-3 molar, data was collected of concent

ration versus time for this reaction. A plot of 1/[A]t versus time resulted in a straight line with a slope value of 3.60 × 10-2 M-1s-1. What is the concentration of A after 300 seconds?
a.2.80 × 10-3 molar
b.2.72 × 10-3 molar
c.2.60 × 10-3 molar
d.3.60 × 10-2 molar
Chemistry
1 answer:
SVETLANKA909090 [29]3 years ago
7 0
If the plot of 1/[A] versus time shows a constant slope, this means it is a second-order reaction. The equation would be:
1/[A] - 1/[A]0 = kt
1/[A] - 1/0.0028 = 0.036(300)
1/[A] = 0.00272 = 2.72 x 10^-3 M
This is equivalent to choice B.
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7 0
1 year ago
the chloride of a metal M contains 47.25% of metal 1.0 gram of metal would be displaced from a compound by 0.88 gram of another
GenaCL600 [577]

Answer:

The equivalent weight of M is approximately 31.8 g

The equivalent weight of N is approximately 27.98 g

Explanation:

The given parameters are;

The percentage of the the metal M in in the chloride = 47.25%

Where by the chemical formula for the metal chloride is MClₓ, we have;

47.25% of the mass of MClₓ = Mass of M = W

Therefore, we have;

\dfrac{0.4725}{W} = \dfrac{1}{W + 35.5 \cdot x}

0.4725 × (W +  35.5·x) = W

0.4725·W + 0.4725×35.5×x = W

W - 0.4725·W  = 16.77·x

0.5275·W = 16.77·x

W/x = 16.77/0.5275 = 31.799 = The equivalent weight of M

The equivalent weight of M = 31.799 ≈ 31.8 g

Given that 1 gram of M is displaced by 0.88 gram of N, then the equivalent weight of N that will displace 31.799 = 0.88 × 31.799 ≈ 27.98 g

The equivalent weight of N = 27.98 g.

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