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-BARSIC- [3]
3 years ago
5

Giving out 56 points! What's the top color of a rainbow?

Chemistry
2 answers:
lys-0071 [83]3 years ago
8 0

❤️Hello!❤️ Red! Then orange, yellow, green, blue, and purple! Hope this helps! ↪️ Autumn ↩️

Anvisha [2.4K]3 years ago
7 0

If you look at a rainbow, the answer is Red. Also, Violet is on the bottom end.

<h2><u><em>Hope this helps</em></u></h2>
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2. A block of material has a volume of 2 m3. It has a mass of 1 × 104 kg. Calculate the density of the material sample and expre
maks197457 [2]
Density = mass / volume

D = 1 x 10⁴ / 2

D = 5000 kg/m³ in g/cm³:

1 kg/m³ ---------------- 0.001 g/cm³
5000 kg/m³ ----------- ??

5000 x 0.001 / 1 =>  5.0 g/cm³

hope this helps!
7 0
3 years ago
2. Which test for iron(II) ions is conclusive ​
krok68 [10]

Answer:

please brainlist answer

Explanation:

The addition of K 3 Fe(CN) 6 to a solution causes the formation of a deep blue precipitate which indicates that iron(II) ions are present.

5 0
2 years ago
Read 2 more answers
If element A has an ionic charge of +2 and element B has an ionic charge of -3, what will be the formula for the compound create
Softa [21]
A3B2 because the oxidation numbers are the same as ionic charge just switch symbol and number. Then use the cross cross method and you get A3B2.
8 0
3 years ago
Earth is unique because it is the _____.
astraxan [27]

Answer:

B. The only planet to support life.

Explanation:

5 0
3 years ago
Read 2 more answers
1) What mass of Na2CO3 is required to make 50cc of its seminormal solution?
love history [14]

Answer:

m=1.325gNa_2CO_3

Explanation:

Hello,

In this case, by considering the given seminormal solution, we infer it is a 0.5-N solution which means that we can obtain the equivalent grams as shown below for the 55 cc (0.055 L) volume:

eq-g=0.5eq-g/L*0.050L=0.025eq-g

Next, since sodium carbonate has two sodium ions with a +1 oxidation state each, we can obtain the moles:

mol=0.025eq-gNa_2CO_3*\frac{1molNa_2CO_3}{2eq-gNa_2CO_3}\\ \\mol=0.0125molNa_2CO_3

Finally, the mass is computed by using its molar mass (106 g/mol)

m=0.0125molNa_2CO_3*\frac{106gNa_2CO_3}{1molNa_2CO_3} \\\\m=1.325gNa_2CO_3

Regards.

7 0
3 years ago
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