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zmey [24]
4 years ago
14

Do all atoms bond in the same way?

Physics
2 answers:
statuscvo [17]4 years ago
4 0
No each atom bonds in a different way according to what does it bonds with
jeka57 [31]4 years ago
4 0
Not all atoms bond in the same way.
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Which pair shows processes that are the reverse of one another?
ale4655 [162]
Condensation and evaporation would most likely be the answer
5 0
4 years ago
Read 2 more answers
A classroom has 24 fluorescent bulbs, each of which is 32 W. how much energy does it take to light the room for a minute?(unit=J
Alina [70]

The energy prdoduced by the 24 bulbs is 46,080 J

Explanation:

Power is defined as the ratio between the energy produced and the time taken:

P=\frac{E}{t}

where

E is the energy

t is the time

In this problem, the power of each bulb is

P = 32 W

Therefore, in a time of

t = 1 min = 60 s

The energy produced by each bulb is

E=Pt=(32)(60)=1920 J

Here we have 24 bulbs, so the total energy produced is

E=24(1920)=46,080 J

Learn more about power and energy here:

brainly.com/question/7956557

#LearnwithBrainly

5 0
3 years ago
What is the pressure 200m below the surface of liquid of density 2300kg/m^3?
Lunna [17]

Answer:

h−200m

p−1060kg/m

3

 

g−9.8m/s

2

Patm:−1.013×10 N/m2

FORMULA:

P=P

0

​

+hpg

= 1.013×10+200×1060×9.8

= 21.789×10

5

N/m

2

 

Explanation:

4 0
3 years ago
A change of temperature of 20 C is equivalent to a change in thermodynamic temperature of
Leto [7]

Answer:

20 K

Explanation:

It is given that,

The change in temperature is 20 C.

We need to find the change in thermodynamic temperature.

If teperauture T₁ = 0° C = 0+273 = 273 K

T₂ = 20° C = 20 + 273 = 293 K

The change in temperature,

\Delta T=T_2-T_1\\\\=293-273\\\\=20\ K

So, the change in temperature of 20°C is equivalent to 20 K.

7 0
3 years ago
In an NMR experiment, the RF source oscillates at 34 MHz and magnetic resonance of the hydrogen atoms in the sample being in- ve
choli [55]

Answer:

B_{int}=-0.015T

Explanation:

From the question we are told that:

RF source oscillation speed \sigma= 34 MHz

The external field Bext =0.78 T.

Pro- ton magnetic moment component \mu=1.41 X 10-26 J/T

Generally the equation for magnitude of B_{int} is mathematically given by

B_{int}=B_{ext}-\frac{h\triangle \sigma}{2 \mu}

B_{int}=0.78-\frac{6.6*10^{-34}*34*10^6}{2*1.41*10^{26}}

B_{int}=0.78-0.7957

B_{int}=-0.015T

6 0
3 years ago
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