What is the chemical formula for ammonium hydroxide
1 answer:
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Answer:
The frequency of the oscillations in terms of fo will be f2=fo/3
E xplanation:
T=
=1:3
⇒f2=fo\3
Here frequency f is inversely poportional to square root of mass m.
so the value of remainder of frequency f2 and fo is equal to 1:3.
⇒ =
⇒ = 1:3
⇒f2=
Answer:
The maximum potential difference is 186.02 x 10¹⁵ V
Explanation:
formula for calculating maximum potential difference
where;
Ke is coulomb's constant = 8.99 x 10⁹ Nm²/c²
k is the dielectric constant = 2.3
b is the outer radius of the conductor = 3 mm
a is the inner radius of the conductor = 0.8 mm
λ is the linear charge density = 18 x 10⁶ V/m
Substitute in these values in the above equation;
Therefore, the maximum potential difference this cable can withstand is 186.02 x 10¹⁵ V