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andrey2020 [161]
3 years ago
9

What is the chemical formula for ammonium hydroxide

Physics
1 answer:
hoa [83]3 years ago
8 0
NH4OH is the answer. Hope this helps you.
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3) A 900N mountain climber scales a 100m cliff. How much work is done by the mountain climber?
Y_Kistochka [10]

Answer:

90 kJ

Explanation:

Work = force × distance

W = (900 N) (100 m)

W = 90,000 J

W = 90 kJ

4 0
3 years ago
Read 2 more answers
You are traveling on an airplane. The velocity of the plane with respect to the air is 110.0 m/s due east. The velocity of the a
Mice21 [21]
1. Vpa = 180m/s. @ 0 deg.
  Vag = 40m/s @ 120 deg,CCW.


<span> Vpg = Vpa + Vag,
 Vpg = (180 + 40cos120) + i40sin120,
  Vpg = 160 + i34.64,
 Vpg=sqrt((160)^2 + (34.64)^2)=163.7m/s.
</span>
<span>2. tanA = Y / X = 34.64 / 160 = 0.2165,
  A = 12.2 deg,CCW. = 12.2deg. North of East. </span>

3.  1 hr = 3600s. <span>d = Vt = 163.7m/s * 3600s = 589,320m.

hope this helps</span>
8 0
3 years ago
An excited hydrogen atom releases an electromagnetic wave to return to its normal state. You use your futuristic dual electric/m
masya89 [10]

Answer: the magnetic wave will travel out of the screen.

Explanation:

Electric field direction is perpendicular to the magnetic field direction. Both are also perpendicular to the direction of the particles.

Using right hand rule to solve this problem,

This pointed finger depicts the electric field direction which the curly fingers depict the direction of the magnetic field. The pointed thumb will depict the direction in which the wave travel. Which is out of the screen.

8 0
3 years ago
The energy of the electron in a hydrogen atom can be calculated from the Bohr formula: In this equation stands for the Rydberg e
labwork [276]

Answer:

Wavelength,\lambda=657\ nm

Explanation:

The energy of the electron in a hydrogen atom can be calculated from the Bohr formula as :

E=\dfrac{-R}{n^2}.............(1)

Where

R is the Rydberg constant

n is the number of orbit

We need to find the wavelength of the line in the absorption line spectrum of hydrogen caused by the transition of the electron from an orbital with to an orbital with n₁ = 2 to an orbital with n₂ = 3.

Equation (1) can be re framed as :

\dfrac{1}{\lambda}=R(\dfrac{1}{n_1^2}-\dfrac{1}{n_2^2})

\dfrac{1}{\lambda}=1.096\times 10^7\times (\dfrac{1}{2^2}-\dfrac{1}{3^2})

\lambda=6.569\times 10^{-7}\ m

or

\lambda=657\ nm

So, the the wavelength of the line in the absorption line spectrum is 657 nm. Hence, this is the required solution.

3 0
3 years ago
The space velocity of a star is 120 km/s and its radial velocity is 72 km/s. what is its tangential velocity?
Marina CMI [18]
You divide 120 and 72 and get 1.67 repeated i think
3 0
3 years ago
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