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Westkost [7]
4 years ago
12

In all measurements, you are looking for values that are accurate. Pretend that a pebble with a known mass of 0.567 g was massed

four times where the following masses were obtained: 0.256 g, 0.723 g, 0.554 g and 0.354 g. Those masses are an example of:__________.
a) being precise but not accurate.
b) being both precise and accurate.
c) being neither precise nor accurate.
d) being accurate but not precise.
Chemistry
1 answer:
givi [52]4 years ago
4 0

Answer:

The correct answer is option c, that is, being neither precise nor accurate.

Explanation:

Obtaining the experimental values that come almost close to the true value is termed as accuracy. On the other hand, precision is obtaining experimental values continuously, which may come either far away or near to the true value.  

Based on the given information, it is clear that 0.554 grams, that is, the third value obtained from the experiment is showing some closeness to the true value, which is 0.567 grams. While, neither any of the other values are close or is coming near to the true value. This shows that the measurements are an illustration of being neither precise nor accurate.  

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1.45 moles of helium gas occupies a volume 18.5 L at a pressure of .85 atm. What is the temperature of the gas in K and °C?
Anon25 [30]

Answer: The temperature of the gas is 132.25K and -140.75°C

Explanation:

Given that:

Volume of helium gas (V) = 18.5L

Temperature of helium gas (T) = ?

Pressure (P) = 0.85 atm

Number of moles (n) = 1.45 moles

Molar gas constant (R) is a constant with a value of 0.082 atm L K-1 mol-1

Then, apply the formula for ideal gas equation

pV = nRT

0.85atm x 18.5L = 1.45 moles x 0.082 atm L K-1 mol-1 x T

15.725 atm•L = 0.1189 atm•L•K-1 x T

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T = 132.25K

Given that temperature in Kelvin is 132.25, convert it to Celsius by subtracting 273

So, T(in Celsius) = 132.25K - 273

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Calculate the mole fraction of the ionic species kcl in the solution.
sp2606 [1]

The question is incomplete, here is the complete question:

Calculate the mole fraction of the ionic species KCl in the solution A solution was prepared by dissolving 43.0 g of KCl in 225 g of water.

<u>Answer:</u> The mole fraction of KCl in the solution is 0.044

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

  • <u>For water:</u>

Given mass of water = 225 g

Molar mass of water = 18 g/mol

Putting values in equation 1, we get:

\text{Moles of water}=\frac{225g}{18g/mol}=12.5mol

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Molar mass of KCl = 74.55 g/mol

Putting values in equation 1, we get:

\text{Moles of KCl}=\frac{43g}{74.55g/mol}=0.577mol

Mole fraction of a substance is given by:

\chi_A=\frac{n_A}{n_A+n_B}

  • <u>For KCl:</u>

Moles of KCl = 0.577 moles

Total moles = [0.577 + 12.5] = 13.077 moles

Putting values in above equation, we get:

\chi_{(KCl)}=\frac{0.577}{13.077}=0.044

Hence, the mole fraction of KCl in the solution is 0.044

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