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pochemuha
3 years ago
13

Which is not a benefit of stretching? decreased flexibility improved tissue strength decreased chance of injury relief for tense

muscles
Physics
2 answers:
tester [92]3 years ago
6 0
Devreased flexibility
dmitriy555 [2]3 years ago
3 0
Decreased flexibility
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The energy transported by a mechanical wave is indicated by which property of the wave?
Ksenya-84 [330]
Your answer would be Amplitude :)
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3 years ago
Read 2 more answers
The power of the kettle was 2.6 kW
faltersainse [42]

Answer:

Cp = 4756 [J/kg*°C]

Explanation:

In order to calculate the specific heat of water, we must use the equation of energy for heat or heat transfer equation.

Q = m*Cp*(T_f - T_i)/t

where:

Q = heat transfer = 2.6 [kW] = 2600[W]

m = mass of the water = 0.8 [kg]

Cp = specific heat of water [J/kg*°C]

T_f  = final temperature of the water = 100 [°C]

T_i = initial temperature of the water = 18 [°C]

t = time = 120 [s]

Now clearing the Cp, we have:

Cp = Q*t/(m*(T_f - T_i))

Now replacing

Cp = (2600*120)/(0.8*(100-18))

Cp = 4756 [J/kg*°C]

7 0
2 years ago
What the answer help mees
Vera_Pavlovna [14]
C. The membrane is inside the cell wall. The cell wall surrounds the membrane.
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3 years ago
Coulomb's Law: Two identical small charged spheres are a certain distance apart, and each one initially experiences an electrost
Ahat [919]

Answer:

The magnitude of electrostatic force on each charge is quarter of the magnitude of initial electrostatic force. ( ¹/₄ F)

Explanation:

The electrostatic force between two charges is given by Coulomb's law;

F = \frac{kQ_1Q_2}{r^2}

where;

Q₁ and Q₂ are the magnitude of the charges

r is the distance between the charges

k is Coulomb's constant

Since the charges are identical;

Q₁ = Q

Q₂ = Q

the electrostatic force experienced by each charge is given by;

F =  \frac{kQ^2}{r^2}

When each of the spheres has lost half of its initial charge;

Q₁ = Q/2

Q₂ = Q/2

F_2 = \frac{k(Q/2)(Q/2)}{r^2}\\\\ F_2 = \frac{k(Q)(Q)}{4r^2}\\\\F_2 = \frac{1}{4} (\frac{kQ^2}{r^2} )\\\\F_2 = \frac{1}{4} (F)

Therefore, the magnitude of electrostatic force on each charge is quarter of the magnitude of initial electrostatic force.

6 0
2 years ago
A particular spring has a spring constant of 25 N/m.
kotegsom [21]

Answer:

<h2>2.8×10^-3</h2>

e.p.e =  \frac{1}{2} k {x}^{2}   \\   = \frac{1}{2}  \times 25 \times (0.015m)^{2}  \\  = 0.0028125

<u>0.0028125N</u><u> </u>

8 0
2 years ago
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