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ANEK [815]
3 years ago
6

A uniform yardstick, 3 feet, weighing 1.00 pound is hung vertically from a nail through a hole in one end. The lower end is pull

ed aside by horizontal force F, of such magnitude that the stick makes an angle of 37 ° with the vertical. Find:The horizontal component of the force exerted by the nail on the stick."

Physics
1 answer:
lozanna [386]3 years ago
5 0

Answer:

F = 0.3766[lb]

Explanation:

In order to solve this problem, we must perform a static analysis, draw a free body diagram and analyze the forces acting on the yardstick.

In the attached free body diagram we can see these forces, then we can perform a sum of moments at point A of the yardstick.

The horizontal distance can be found using the distance and the angle:

x = 3*sin(37)

x = 1.805[ft] and the middle distance will be 0.902[ft]

For the vertical distance we have:

y = 3*cos(37)

y = 2.395[ft]

SM_{A} =0\\0=-(1*0.902)+(F*2.395)\\F = 0.3766[lb]

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Answer:

The temperature of silver at this given resistivity is 2971.1 ⁰C

Explanation:

The resistivity of silver is calculated as follows;

R_t = R_o[1 + \alpha(T-T_o)]\\\\

where;

Rt is the resistivity of silver at the given temperature

Ro is the resistivity of silver at room temperature

α is the temperature coefficient of resistance

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R_t = R_o[1 + \alpha(T-T_o)]\\\\\R_t = 1.59*10^{-8}[1 + 0.0038(T-20)]

Resistivity of iron at room temperature = 9.71 x 10⁻⁸ ohm.m

When silver's resistivity becomes 2 times the resistivity of iron, we will have the following equations;

R_t,_{silver} = 2R_o,_{iron}\\\\1.59*10^{-8}[1 + 0.0038(T-20)] =(2 *9.71*10^{-8})\\\\\ \ (divide \ through \ by \ 1.59*10^{-8})\\\\1 + 0.0038(T-20) = 12.214\\\\1 + 0.0038T - 0.076 = 12.214\\\\0.0038T +0.924 = 12.214\\\\0.0038T  = 12.214 - 0.924\\\\0.0038T = 11.29\\\\T = \frac{11.29}{0.0038} \\\\T = 2971.1 \ ^0C

Therefore, the temperature of silver at this given resistivity is 2971.1 ⁰C

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