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ch4aika [34]
3 years ago
11

A truck accelerates 2 m/s2 when it is empty. If the truck is filled so that it has twice the mass and the same amount of net for

ce is applied, how much will the truck accelerate?
8 m/s2
1 m/s2
4 m/s2
2 m/s2

Physics
2 answers:
mina [271]3 years ago
6 0

This is a conceptual problem, I’ll try to upload a picture:

hram777 [196]3 years ago
5 0

Answer :

a = 1 m/s^2

Explanation:

Given information

Net force is a constant

The mass of the truck is m_{o}

Initial acceleration a_{o}= 2 m/s^{2}

The mass of the truck is increased twice as much

F_{net}= m_{o} a_{o} = ma

F_{net}= m_{o} a_{o} = 2m_{o}a

a=\frac{a_{o} } {2}

a = 2/2

a = 1 m/s^{2}

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Shalnov [3]

Explanation:

Let 'F' be force acting perpendicularly, 'A' be the area and 'P' be the pressure exerted.

Then,

Pressure is directly proportional to the the force acting perpendicularly i.e.

P ∝ F ............. (i)

Pressure is inversely proportional to the area on which force acts i.e.

P ∝ 1/A ........... (ii)

Combining equations (i) and (ii),

P ∝ F/A

or, P = K × F/A [where K is a constant]

If F is 1N, A is 1m² and P is 1 N/m², then K is 1.

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6 0
3 years ago
A spring (k = 200 N/m) is fixed at the top of a frictionless plane inclined at angle θ = 33 °. A 1.2 kg block is projected up th
Serga [27]

Answer:

Explanation:

Initial kinetic energy = 29 J

work done against gravity = mgsin33 x d  , m is mass of the block

= 1.2 x 9.8 sin 33 x .9

= 5.76 J

potential energy stored in compressed spring

= 1/2 k x², k is spring constant and x is compression

= .5 x 200 x .3²

= 9

energy left = 29 - ( 5.76 + 9 )

= 14.24 J

b )

energy stored in spring when compression is .4 m

= 1/2 x 200 x .4²

= 16 J

required kinetic energy = 16 + 5.76

= 21.76 J

Block must be projected with energy of 21.76 J .

7 0
3 years ago
A 384 m long train is moving on a straight track with a speed of 77.3 km/h. The engineer applies the brakes at a crossing, and l
solniwko [45]

Answer:

The time the train blocked the crossway is

0.007934h=0.476 min=28.6 s

Explanation:

The average speed is given by

V= (Vi+Vf)/2

and

V= dx/dt

Where

Vi= initial speed

Vf= final speed

dx= change of position=0.384 km

dt=time the train blocked the crossway

dt=2dx/(Vi+Vf)

dt=2*0.384 km/(77.3 +19.5) km/h

dt=0.007934h

dt=0.007934h*(60min/1h)=0.476 min

dt=0.476 min*(60s/1min)=28.6 s

7 0
3 years ago
Which term describes an area of low density in a longitudinal wave?
LiRa [457]

Answer:

Explanation:

Low density is an area of rarefaction.

6 0
3 years ago
Read 2 more answers
A revolutionary war cannon, with a mass of 2090 kg, fires a 16.7 kg ball horizontally. The cannonball has a speed of 113 m/s aft
OLEGan [10]

Answer:

0.90291 m/s

0.45055 m/s

Explanation:

m_1 = Mass of canon = 2090 kg

m_2 = Mass of ball = 16.7 kg

v_1 = Velocity of canon

v_2 = Velocity of ball = 113 m/s

In this system the momentum is conserved

m_1v_1=m_2v_2\\\Rightarrow v_1=\dfrac{16.7\times 113}{2090}\\\Rightarrow v_1=0.90291\ m/s

The velocity of the cannon is 0.90291 m/s

Applying energy conservation

\dfrac{1}{2}m_1v_1^2+\dfrac{1}{2}m_2v_2^2=\dfrac{1}{2}m_2v^2\\\Rightarrow m_1v_1^2+m_2v_2^2=m_2v^2\\\Rightarrow v_2=\sqrt{\dfrac{m_1v_1^2+m_2v_2^2}{m_2}}\\\Rightarrow v_2=\sqrt{\dfrac{2090\times 0.90291^2+16.7\times 113^2}{16.7}}\\\Rightarrow v_2=113.45055\ m/s

The ball would travel 113.45055-113 = 0.45055 m/s faster

6 0
4 years ago
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