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3 years ago

Which term describes an area of low density in a longitudinal wave?

Physics

2 answers:

LiRa [457]3 years ago

6 0

Answer:

Explanation:

Low density is an area of rarefaction.

kicyunya [14]3 years ago

6 0

Answer: rarefaction

Explanation: correct answer on a p e x

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Two ice skaters push off against one another starting from a stationary position. The 54.1-kg skater acquires a speed of 0.375 m

asambeis [7]

Answer:

0.338125 m/s

Explanation:

Applying,

Law of conservation of momentum

m'v' = mv............ Equation 1

Where m' = mass of the first skater, v' = velocity of the first skater, m = mass of the second skater, v = velocity of the second skater.

make v the subject of the equation

v = m'v'/m........... Equation 2

From the question,

Given: m' = 54.1 kg, v' = 0.375 m/s, m = 60 kg

Substitute these values into equation

v = (54.1×0.375)/60

v = 20.2875/60

v = 0.338125 m/s

3 0

3 years ago

A mixture can be classified as a solution, suspension, or coiled based on the: A. Number or particles it contains. B. Size of it

gladu [14]

According to chapter 1 in the mixture of particles Article a mixture has to contain a serten size to mix with another particle so i would go with B size of the largest particle

5 0

3 years ago

A cruise ship is having troubles with buoyancy. What is a reasonable solution? A. Increase the weight of the ship above water B.

Setler [38]

If a cruise ship is having troubles with buoyancy, then spread the weight of the ship over a greater volume.

Answer: Option D

<u>Explanation: </u>

Buoyancy is the upward thrusting phenomenon of water acting on any object immersed partially or fully in water body. Hence, it creates the buoyant forces that is inversely proportionate to the immersing body's density. If the immersing body's density is higher than the density of the immersing medium then the body will get completely immersed in the water.

Similarly, in case of less, the buoyant forces act on the body will prevent it from complete immersion and allow it to float on water. Mostly cruise ships and other navy vessels use this phenomenon to keep on floating on surface of water.

In the present condition, the solution for buoyancy problem faced by a cruise ship can be solved by decreasing the density of the ship. And the ship's density can be decreased by increasing the ship's volume or by spreading the ship's weight over a greater volume.

5 0

3 years ago

Read 2 more answers

I measured my pet dog (Mickey) to be able to run the length of my backyard 500 in 12 seconds. At this rate, how many miles can m

Georgia [21]

The dog runs 300240 miles.

Rate refers to the pace at which something happens. We know that the easiest way to obtain the rate is by the use of proportion. Now we have been told that the dog is able to run 500 miles in 12 seconds.

If the dog runs 500 miles in 12 seconds

The dog runs x miles in 1 second

x = 500 * 1/12

x = 41.7 miles

In two hours we have 2 * 60 * 60 = 7200 seconds

If the dog runs 41.7 miles in 1 second

The dog runs x miles in 7200 seconds

x = 41.7 miles * 7200 seconds/ 1 second

x = 300240 miles

Learn more about proportion:brainly.com/question/2548537

#SPJ1

4 0

2 years ago

1. A truck with a mass of 8, 000 kg is traveling at 26.8 m/s when it hits the brakes. A.)What is the momentum of the truck befor

NikAS [45]

Answer:

1. A.) The moment of the truck before it hits the brakes is 214,400 kg·m/s

B.) The force it takes to stop the truck is approximately 17,290.4 N

Explanation:

1. A.) The given parameters are;

The mass of the truck, m = 8,000 kg

The velocity of the truck when it hits the brakes, u = 26.8 m/s

Momentum = Mass × Velocity

The moment of the truck = The mass of the truck × The velocity of the truck

Therefore;

The moment of the truck before it hits the brakes = 8,000 kg × 26.8 m/s = 214,400 kg·m/s

B.) The amount of momentum lost when the truck comes to a stop = The initial momentum of the truck

The time it takes the truck to come to a complete stop, t = 12.4 s

The deceleration, "a" of the truck is given by the following kinematic equation of motion

v = u - a·t

Where;

v = The final velocity of the truck = 0 m/s

u = The initial velocity = 26.8 m/s

a = the deceleration of the truck

t = The time of deceleration of the truck = 12.4 s

Substituting the known values gives;

0 = 26.8 - a × 12.4

Therefore;

26.8 = a × 12.4

a = 26.8/12.4 ≈ 2.1613

The deceleration (negative acceleration) of the truck, a ≈ 2.1613 m/s²

Force = Mass × Acceleration

The force required to stop the truck = The mass pf the truck × The deceleration (negative acceleration) given to the truck

∴ The force it takes to stop the truck = 8,000 kg × 2.1613 m/s² ≈ 17,290.4 N.

8 0

3 years ago