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Sedaia [141]
2 years ago
9

If you are good at activities that require agility, what are you able to do well?

Physics
1 answer:
Mrac [35]2 years ago
5 0

Answer:

2

Explanation:

agility is the ability to zoom fast and do fast zoomy stuff

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when do you use cos and sin in situations like these? is horizontal always cos and vertical always sin?
Andreas93 [3]

Answer:

yes

Explanation:

this is simple

the horizontal line is adjacent

the vertical line is opposite

recall that cos x=adj/hyp

adj=hyp(cos x)

while opp=hyp(sin x)

8 0
3 years ago
The mass of the bicycle and rider is 60 kg and the total area of the tyres in contact with
AleksAgata [21]

Answer:

a little

Explanation:

First of all, it's not how you spell "tyres", it is tires.

Second of all, you already know the Mass so what you need to find out now is  contact the road. You Know that your number and letter are squared so that would turn into 6m x 2.4. Then you do the math do continue on to finish it. Have a great day!! Good luck with the answer!!

3 0
3 years ago
Question 2 of 34
tatiyna

You can find the magnitude of the resultant vector : (B). By adding the magnitudes of the two vectors

<h3>Meaning of Vectors</h3>

A vector can be defined as any quantity which possesses magnitude and also has direction.

A Vector quantity is very useful because This type of quantity gives more details to the student or teacher analyzing it.

Lear more about Vectors: brainly.com/question/25705666

#SPJ1

8 0
2 years ago
Question 1 of 4 Attempt 4 The acceleration due to gravity, ???? , is constant at sea level on the Earth's surface. However, the
Evgen [1.6K]

Answer:

g(h) = g ( 1 - 2(h/R) )

<em>*At first order on h/R*</em>

Explanation:

Hi!

We can derive this expression for distances h small compared to the earth's radius R.

In order to do this, we must expand the newton's law of universal gravitation around r=R

Remember that this law is:

F = G \frac{m_1m_2}{r^2}

In the present case m1 will be the mass of the earth.

Additionally, if we remember Newton's second law for the mass m2 (with m2 constant):

F = m_2a

Therefore, we can see that

a(r) = G \frac{m_1}{r^2}

With a the acceleration due to the earth's mass.

Now, the taylor series is going to be (at first order in h/R):

a(R+h) \approx a(R) + h \frac{da(r)}{dr}_{r=R}

a(R) is actually the constant acceleration at sea level

and

a(R) =G \frac{m_1}{R^2} \\ \frac{da(r)}{dr}_{r=R} = -2 G\frac{m_1}{R^3}

Therefore:

a(R+h) \approx G\frac{m_1}{R^2} -2G\frac{m_1}{R^2} \frac{h}{R} = g(1-2\frac{h}{R})

Consider that the error in this expresion is quadratic in (h/R), and to consider quadratic correctiosn you must expand the taylor series to the next power:

a(R+h) \approx a(R) + h \frac{da(r)}{dr}_{r=R} + \frac{h^2}{2!} \frac{d^2a(r)}{dr^2}_{r=R}

6 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%5Cboxed%7B%5Ccolor%5Cred%5Chuge%5Ctt%5Cbold%5Cpurple%7BQuestion%7D%7D" id="TexFormula1" title
otez555 [7]

Answer:

Inertia : a property of matter by which it continue in its existing state of rest or uniform motion in a straight line, unless that state is changed by external force.

HOPE ITS HELPS!!

7 0
2 years ago
Read 2 more answers
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