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alexgriva [62]
3 years ago
6

As the mass of a sample increases, the number of moles present in the sample (increases)

Chemistry
2 answers:
Alex Ar [27]3 years ago
3 0

Answer:

true. m (↑) ⇒ n (↑)

Explanation:

  • mass (m) ≡ moles ( n) × moleculas weight ( Mw )

In the previous expression, we appreciate that the mass is directly proportional to the moles; therefore, if the mass of the sample increases, its number of moles will also increase, since the molecular weight is always constant.

∴ m (↑) ⇒ n (↑)

grin007 [14]3 years ago
3 0

Answer:

increases

Explanation:

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In a boys hostel, 1206 eggs were bought for breakfast for the students. How many moles of eggs does this represent?
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Answer:

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Here, it has been asked how many eggs are in one mole of eggs. The eggs represent the unit which can be atom, ion or molecule. So by the definition of mole, 6.022×1023number of eggs are present in one mole of eggs.

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Radio waves travel at the speed of light which is 3.00 x 10^8. How many minutes does it take for a radio message to reach saturn
ryzh [129]

Answer:

43.89 min

Explanation:

Given that:-

The speed of light = 3.00\times 10^8\ m/s

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The conversion of distance in km to distance into m is shown below as:-

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Thus,

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3 0
3 years ago
stbank, Question 075 Get help answering Molecular Drawing questions. Compound A, C6H12 reacts with HBr/ROOR to give compound B,
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Answer:

Explanation:

In this case we want to know the structures of A (C6H12), B (C6H13Br) and C (C6H14).

A and C reacts with two differents reagents and conditions, however both of them gives the same product.

Let's analyze each reaction.

First, C6H12 has the general formula of an alkene or cycloalkane. However, when we look at the reagents, which are HBr in ROOR, and the final product, we can see that this is an adition reaction where the H and Br were added to a molecule, therefore we can conclude that the initial reactant is an alkene. Now, what happens next? A is reacting with HBr. In general terms when we have an adition of a molecule to a reactant like HBr (Adding electrophyle and nucleophyle) this kind of reactions follows the markonikov's rule that states that the hydrogen will go to the carbon with more hydrogens, and the nucleophyle will go to the carbon with less hydrogen (Atom that can be stabilized with charge). But in this case, we have something else and is the use of the ROOR, this is a peroxide so, instead of follow the markonikov rule, it will do the opposite, the hydrogen to the more substituted carbon and the bromine to the carbon with more hydrogens. This is called the antimarkonikov rule. Picture attached show the possible structure for A. The alkene would have to be the 1-hexene.

Now in the second case we have C, reacting with bromine in light to give also B. C has the formula C6H14 which is the formula for an alkane and once again we are having an adition reaction. In this case, conditions are given to do an adition reaction in an alkane. bromine in presence of light promoves the adition of the bromine to the molecule of alkane. In this case it can go to the carbon with more hydrogen or less hydrogens, but it will prefer the carbon with more hydrogens. In this case would be the terminal hydrogens of the molecules. In this case, it will form product B again. the alkane here would be the hexane. See picture for structures.

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Have a nice day!

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