Answer: There is 125 mL of a 2.0 M CuCl2 solution are needed to make 500 mL of a 0.5 M solution
Explanation:
Given: = 2.0 M, = ?
= 0.5 M, = 500 mL
Formula used to calculate the volume is as follows.
Substitute the values into above formula as follows.
Thus, we can conclude that there is 125 mL of a 2.0 M solution are needed to make 500 mL of a 0.5 M solution.
Step OneFind the moles of HCl
C = 1.0 mol/L
V = 75 mL = 75 / 1000 = 0.75 L
Note the concentration is in Liters.
<em>Formula</em>
n = C*V
<em>Solve</em>
n = 1.0 * 0.075
n = 0.075 moles
Step two Adjust the number of moles of HCl
How every mol of H2 produced, you will require 2 mol of HCl
2/1 = 0.075/x Cross multiply
2x = 0.075 Divide by 2
x = 0.075 / 2
x = 0.0375
moles of H2 <<<<<<<<< Answer
The molarity of the Ca(OH)2 solution is calculated as follows
find the concentration of HCl used from the Ph
that is PH = - log H+= 1.3
H+ = 10^-1.3 = 0.05 M
the moles of HCl = molarity x volume/1000
= 0.05 x 300/1000=0.015 moles
write the reaction equation
that is Ca(OH)2 +2HCl=CaCl2 + 2H20
by use of reacting ratio between Ca(OH)2 to HCl (1:2) the moles of Ca(OH)2 is = 0.015 x1/2=7.5 x10^-3 moles
molarity is therefore = moles /volume in liters
= {( 7.5x10^-3) /50} x1000 = 0.15 M ( answer 5)
Answer:
The rate of the reaction would be halved.
Explanation:
The reaction is first order with respect to reactant A and second order with respect to reactant B. The rate equation is [A][B]^2
If the concentration of A is doubled and the concentration of B is halved, rate = 2 × (1/2)^2 = 2 × 1/4 = 1/2.
The rate would be halved.