Answer:
-5.396Joules
Explanation:
Work is said to be done when a force causes a body to move through a distance and acts in the direction of the force.
Work done = Force × Distance
Given force = mg
Force = 2.20×9.81
Force applied on the string = 21.58N
Distance will be the difference in height = 4.75-5.00
= 0.25m
Negative work done on the pendulum during the first entirely oscillation = 21.58×0.25
= -5.396Joules
Energy is calculated as power*time, so give the wattage of 1200 W (equivalent to 1200 Joules/second) and time of 30 seconds, multiplying these gives 36000 J or 36 kJ of electrical energy.
If electrical charge or current is needed: Power = voltage * current, so given the power of 1200 watts and voltage of 120 V, current is 1200 W / 120 V = 10 Amperes. Charge is calculated by multiplying 10 A*30 s = 300 C.
For a standing wave if both ends are fixed, the wavelength must be such that the length of the string be an exact multiple of a half wavelength.
The longest wavelength must be such that the length of the string must be equal to half a wavelength, and therefore the wavelength must be double the length of the string; That is 240× 2 = 480 cm
The second longest wavelength must be such that the length of the string must be equal to a whole wavelength, so the second longest wavelength must be 240 cm.
The third longest wavelength must be such that the length of the string must be equal to 1.5 times the wavelength, so the wavelength must be 240/1.5 = 160 cm.
Answer:
Experiments showed that increasing the light frequency increased the kinetic energy of the photoelectrons, and increasing the light amplitude increased the current.
Explanation:
The photocurrent increases linearly with the intensity of the incident light but is independent of its frequency. The stopping potential increases linearly with the frequency of the incident light but is independent of its intensity.
Answer:
The current in the ammeter is zero.
(1) is correct option.
Explanation:
Given that,
The capacitor is charged.
We need find the current after closed switched
We know that,
When switch is closed then the capacitor behave as a short circuit, and the all current flows through it. the current is zero.
Then, the ammeter reads zero.
Hence,
The current in the ammeter is zero.
(1) is correct option.