Hello,
<span>A police car parked on the side of the highway emits a 1200 Hz sound that bounces off a vehicle farther down the highway and returns with a frequency of 1250 Hz.
How fast is the vehicle going?
Doppler equation formula: </span>ƒL = ƒS(v - vL)/(v - vS)
The wave returns with a frequency of 1250 Hz, the <span>echo frequency is higher; the car must be traveling towards the police car.
</span><span>The wave echo is coming back towards the police car at the same speed as the sound wave travels towards the moving car so t</span><span>he relative speed between the cars is half of the speed of the echo.
* </span><span>speed of sound equals about 337 m/s </span>
2v / 337 = (1250/1200) - 1
<span>2v = 14.04 m/s </span>
<span>v = 7.02 m/s
</span>
Thus, the vehicle is going 7.02 m/s.
Faith xoxo
Answer:
what do u need help with
Explanation:
A body of mass m moves along X-axis such that its position co-ordiante at any instant t is x = `at^(4)
Answer:
THE ANSWER IS KINETIC ENERGY
I JUST TOOK THE LAB FOR THIS
The positive benefit of the uranium mining will be felt by the people and economy because uranium mining give us enough resource to provide sustainable and low cost method of generating energy.
The environment on the other hand , will only be exposed to the negative impact. If the miners fail to store the waste properly, the uranium could make the environment around it become really toxic and unhabitable.
Answer:
The charge flos through the coil is 0.023C
Explanation:
To solve this problem, it is necessary to apply the concepts related to Faraday's Law in which it is possible to calculate the emf Voltage induced due to a charge in a magnetic field
and Ohm's Law for the calculation of the current based on a given load over time.
Our data are given by:
Where
N is the number of loops, A the area and R the Resistance.
The change in magnetic field can be calculated as,
The Faraday's law of electromagnetic induction is given by definition as,
In the other hand Ohm's law says:
Equating both equations we have
We can re-arrange the equations to solve q, then
Therefore the charge flos through the coil is 0.023C
