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aleksandrvk [35]
3 years ago
12

Calculate the length of a simple pendulum that oscillates with a frequency of 0.4Hz g=10m/s2 , ^=3.142

Physics
1 answer:
earnstyle [38]3 years ago
4 0

Answer:

Explanation:

For simple pendulum the formula is

T=2\pi\sqrt{\frac{l}{g} }

Where T is time period , l is length and g is acceleration due to gravity .

\frac{1}{n} =2\pi\sqrt{\frac{l}{g} }

n is frequency

Putting the values

\frac{1}{.4} =2\pi\sqrt{\frac{l}{10} }

\frac{l}{10} = .1584

l = 1.584 m

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What does the length of a vector arrow represent?
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The length of a vector arrow represents an magnitude
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A ball is traveling 24° above the horizontal at a speed of 12 m/s. What is the vertical component of its speed?
victus00 [196]

Answer:

4.88 m/s

Explanation:

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What is the volume of a bar of soap that is 9 cm long, 5 cm wide, and 2 cm high?
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Answer:

90cm

Explanation:

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3 years ago
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A baseball player friend of yours wants to determine his pitching speed. You have him stand on a ledge and throw the ball horizo
Alla [95]

Answer:

v_{ox}= 19.6\ m/s

Explanation:

Data provided in the question:

Height above the ground, H= 5.0m

Range of the ball, R= 20 m

Initial horizontal velocity = v_{ox}

Initial vertical velocity= v_{oy}  (Since ball was thrown horizontally only)

Acceleration acting horizontally, a_x = 0 m/s²  [ Since no acceleration acts horizontally) ]

Vertical Acceleration, a_y = 9.8 m/s² (Since only gravity acts on it)

Let 't' be the time taken to reach ground

Therefore, using equations of motion, we have

H= v_{oy}t+\frac{1}{2}a_yt^2

5= (0)t+\frac{1}{2}(9.8)t^2

t= \frac{10}{9.8}=1.02 s

Then using Equations of motion for horizontal motion,

R= v_{ox}t+\frac{1}{2}a_xt^2

20= v_{ox}(1.02)+\frac{1}{2}(0)(1.02)^2

v_{ox}= 19.6\ m/s

4 0
2 years ago
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