In middle school, the formula you'll use most often when you're
working with acceleration is . . .
Acceleration = (change in speed during some time) / (time for the change)
B
add them all by direction
13 East
10 West
subtract difference
3 E
Explanation:
W = PE
W = mgh
1500 J = (20 kg) (9.8 m/s²) h
h = 7.65 m
Round as needed.
The average dissipated power in a resistor in a ac circuit is:
![P=I_{rms}^2 R](https://tex.z-dn.net/?f=P%3DI_%7Brms%7D%5E2%20R)
where R is the resistance, and
![I_{rms}](https://tex.z-dn.net/?f=I_%7Brms%7D)
is the root mean square current, defined as
![I_{rms} = \frac{I_0}{\sqrt{2}}](https://tex.z-dn.net/?f=I_%7Brms%7D%20%3D%20%20%5Cfrac%7BI_0%7D%7B%5Csqrt%7B2%7D%7D%20)
where
![I_0](https://tex.z-dn.net/?f=I_0)
is the peak value of the current. Substituting the second formula into the first one, we find
![P=( \frac{I_0}{\sqrt{2} } )^2 R = \frac{1}{2} I_0^2 R](https://tex.z-dn.net/?f=P%3D%28%20%5Cfrac%7BI_0%7D%7B%5Csqrt%7B2%7D%20%7D%20%29%5E2%20R%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20I_0%5E2%20R%20)
and if we re-arrange this formula and use the data of the problem, we can find the value of the peak current I0:
The vanishing of an ionic solid (like table salt) would be an example of acting like a solvent