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Gnom [1K]
3 years ago
8

Five basket ball teams are playing in a tournament. The teams will play with each other only one time. How many games will be pl

ay by the end of the tournament?
Physics
1 answer:
77julia77 [94]3 years ago
3 0

<em>Ten games</em> will be played.

The first team can be any one of 5 .  For each of those, the opponent can be any one of the other 4 .

Number of ways to pair them up = (5 x 4) = 20 ways .

<em>BUT</em> ... Whether the Reds play the Blues, or the Blues play the Reds, it's the SAME GAME.  Each possible game shows up twice in the list of 20 ways.  So there are really only 10 different pairs ==> <em>10 games</em> .

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Given that,

Mass of object = 9.90 kg

Time =5.40 s

Suppose the force is (2.00i + 9.00j + 5.30k) N, initial position is (2.70i - 2.90j + 5.50k) m and final position is (-4.10i + 3.30j + 5.40k) m.

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Put the value into the formula

s= (-4.10i + 3.30j + 5.40k)-(2.70i - 2.90j + 5.50k)

s= -6.80i+6.20j-0.1k

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Using formula of work done

W=F\cdot s

Put the value into the formula

W=(2.00i + 9.00j + 5.30k)\cdot (-6.80i+6.20j-0.1k)

W=-13.6+55.8-0.53

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P=\dfrac{W}{t}

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P=\dfrac{41.67}{5.40}

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Put the value into the formula

\theta=\cos^{-1}\dfrac{(-4.10i + 3.30j + 5.40k)\cdot(2.70i - 2.90j + 5.50k)}{7.54\times6.778})

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Hence, (a). The work done on the object by the force in the 5.40 s interval is 41.67 J.

(b). The average power due to the force during that interval is 7.71 Watt.

(c).  The angle between vectors is 79.7°

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