Question

A gas has a pressure of 500.0 Torr at 35.0 °C. What is the temperature at standard pressure?

Answer 1

Answer:

466.65 K

Explanation:

Using the formula of  Pressure law,

P/T = P'/T'.................... Equation 1

Where P = Intial pressure of gas, T = Initial temperature of gas, P' = Final pressure of gas, T' = Final temperature of gas.

make T' The subeject of equation 1

T' = (P'T)/P................... Equation 2

From the question,

Given: P = 500 Torr = (500×133.322) N/m² = 66661 N/m², T = 35°C = (35+273) = 308 K, P' = 101000 N/m²( Standard pressure)

Substitute these values into equation 2

T' = (101000×308)/66661

T' = 466.65 K