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ankoles [38]
3 years ago
6

Which two types of matter are pure substances? A homogenous mixtures and elements B solutions and compounds C elements and compo

unds D mixtures and elements
Chemistry
1 answer:
ira [324]3 years ago
7 0

Answer:

elements and compounds

Explanation:

Pure substances contain the same type of particles in the substance. All the component particles in a pure substance have exactly the same composition and are present in exactly the same proportion.

An element consists of atoms of the a particular element in a specified arrangement. A compound is composed of atoms of elements joined together in a unique way and that arrangement is maintained throughout the substance. Hence these are pure substances.

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How many centimeters are in .479 kilometers
trapecia [35]

Answer:

47900 cm

General Formulas and Concepts:

<u>Chemistry</u>

  • Base 10 Decimal System
  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

0.479 km

<u>Step 2: Identify Conversions</u>

1 km = 1000 m

1 m = 100 cm

<u>Step 3: Convert</u>

<u />0.479 \ km(\frac{1000 \ m}{1 \ km} )(\frac{100 \ cm}{1 \ m} ) = 47900. cm

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules.</em>

47900. cm ≈ 47900 cm

7 0
3 years ago
Someone plz help me !!<br><br> Science <br> Or<br> Bias?
Artist 52 [7]
1st one is Science and the 2nd one is Bias
8 0
3 years ago
for the reaction HCI+NaOH➡️NaCi+H2O, how many moles of hydrochloric acid are required to produce 150 g. of water?
Ne4ueva [31]

Answer: 8.33 mol of HCl (Hydrochloric Acid)

Explanation:

150 g H2O  x __1 mol__ x __1 mol HCl__  =  8.33 mol of HCl

                         18.016 g        1 mol H2O

6 0
3 years ago
А
Anna71 [15]

Answer:

This flexible ability is important because it allows the cell to survive in differing environments, such as when immersed in water over long periods of time.

4 0
2 years ago
Help me. correct answer will be marked as brnlst
Vlada [557]

Answer:

PCI3

Explanation:

It does not obey the octet rule on the nitrogen atom.

5 0
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