Answer:
Wouldn't rust because zinc will lose electrons more readily than iron and will therefore oxidize first. 
Explanation:
This process whereby rusting of steel is prevented by coating the steel with a layer of zinc is known as galvanization.
Now, in this process, the steel object will be coated in a thin layer of zinc. This coating will prevent oxygen and water from reaching the underneath metal since the zinc will also act as a sacrificial metal. 
Now, Zinc is used because it has a lower reduction potential than iron and thus it will get easily more oxidized than iron. Which means the zinc will lose electrons more readily than iron. 
Also, since zinc has a lower reduction potential, it is therefore the more active metal. Thus, even if the zinc coating is scratched and the steel is exposed to moist air, the zinc will still get to oxidize before the iron. 
 
        
             
        
        
        
Answer: El carbono, que en estado sólido, puede adoptar muchas formas alotrópicas, siendo las más comunes el diamante (red tridimensional) y el grafito (láminas), aunque también puede formar nanoestructuras en forma de balón de fútbol (fullerenos) o tubos diminutos (nanotubos de carbono), entre otras posibilidades.
Explanation:
 
        
             
        
        
        
Use photomath. I would really recommend it! Hope this helps!
        
                    
             
        
        
        
Answer:
(a) Pair 1: H₂S and HS⁻
     Pair 2: NH₃ and NH₄⁺
(b) Pair 1: HSO₄⁻ and SO₄⁻
     Pair 2: NH₃ and NH₄⁺
(c) Pair 1: HBr and Br⁻
     Pair 2: CH₃O⁻ and CH₃OH
(d)  Pair 1: HNO₃ and NO₃⁻
      Pair 2: H₃O⁺
Explanation:
When an acid loses its proton (H⁺), a conjugate base is produced. 
When a base accepts a proton (H⁺), it forms a conjugate acid. 
(a) H₂S is an acid. When it loses a proton, it forms the conjugate base HS⁻. 
     NH₃ is a base. When NH₃ gains a proton, it forms the conjugate acid NH₄⁺
(b) The acid HSO₄⁻ loses a H⁺ ion and forms the conjugate base SO₄²⁻.
      The base NH₃ accepts a H⁺ ion to form the conjugate acid NH₄⁺.
(c) HBr is an acid. When loses the H⁺ ion, it forms the conjugate base Br⁻.
    CH₃O⁻ accepts a H⁺ ion to form the conjugate acid CH₃OH. 
(d) HNO₃ loses a proton to form the conjugate base NO₃⁻.
     H₂O gains a proton to form the conjugate acid H₃O⁺.